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natita [175]
3 years ago
13

Find the product (4x-3) (3x+8)

Mathematics
1 answer:
m_a_m_a [10]3 years ago
4 0

Hi there!

Assuming "Find the product" means multiplying (4x-3) by (3x+8) and factor to it's simplest form the answer would be:

12x²+23x-24

The way you solve this is by using the distributive property of multiplication as shown below:

Start by multiplying -3 from (4x-3) by everything in (3x+8)

3x*(-3) = -9x

8*(-3) = -24

Once you've done that you then multiply everything 4x

4x*8 = 32x

4x*3x = 12x²

(Note: when multiplying two of the same variables like x it means you are multiplying x by itself which is the same as x²)

When you put all of this together it looks like this

12x²+32x-9x-24

from there we combine like terms

32x-9x = 23x

to get

12x²+23x-24

I hope this helps!

God bless,

ASIAX

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Answer:

So, marta will sprint 225 yards.

Step-by-step explanation:

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FinnZ [79.3K]

Answer:

{x = 1, y = -5

Step-by-step explanation:

Solve the following system:

{-3 x - 3 y = 12 | (equation 1)

{3 y - 9 x = -24 | (equation 2)

Swap equation 1 with equation 2:

{-(9 x) + 3 y = -24 | (equation 1)

{-(3 x) - 3 y = 12 | (equation 2)

Subtract 1/3 × (equation 1) from equation 2:

{-(9 x) + 3 y = -24 | (equation 1)

0 x - 4 y = 20 | (equation 2)

Divide equation 1 by 3:

{-(3 x) + y = -8 | (equation 1)

{0 x - 4 y = 20 | (equation 2)

Divide equation 2 by 4:

{-(3 x) + y = -8 | (equation 1)

{0 x - y = 5 | (equation 2)

Multiply equation 2 by -1:

{-(3 x) + y = -8 | (equation 1)

{0 x+y = -5 | (equation 2)

Subtract equation 2 from equation 1:

{-(3 x)+0 y = -3 | (equation 1)

{0 x+y = -5 | (equation 2)

Divide equation 1 by -3:

{x+0 y = 1 | (equation 1)

{0 x+y = -5 | (equation 2)

Collect results:

Answer:  {x = 1 , y = -5

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Answer:

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