We know that perimeter rectangle A=2*[5+3]-----> 16 in
let x------> length side rectangle B y-------> width side rectangle B so x=6+y-------> equation 1 16=2[x+y]------> equation 2 <span>I substitute 1 in 2 </span>16=2*[6+y+y]-------> 16=2*[6+2y]-----> 16=12+4y-----> 4y=16-12 y=4/4--------> y=1 in x=6+1---->x=7 in
the answer is the dimensions of rectangle B are length side is 7 in width side is 1 in
