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yaroslaw [1]
4 years ago
11

Simplify 10/16 to lowest terms and find an equivalent fraction that has a denominator of 32?

Mathematics
1 answer:
goblinko [34]4 years ago
3 0

Answer:

The lowest fraction for \frac{10}{16} is \frac{5}{8} and a equivalent fraction with denominator of 32 is \frac{20}{32}.

Step-by-step explanation:

First, to have the fraction to the lowest terms we will have to divide the numerator and denominator by 2, this is:

\frac{10/2}{16/2}=\frac{5}{8}

As can be seen the expression couldn't be simplified more because there is no a common number that could divide the numerator and denominator.

Second, to have an equivalent fraction with 32 in the denominator we will have to multiply the denominator by 2 and of course the numerator, this is:

\frac{10*2}{16*2}=\frac{20}{32}

The lowest fraction for \frac{10}{16} is \frac{5}{8} and a equivalent fraction with denominator of 32 is \frac{20}{32}.

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MaRussiya [10]
32ft you do 8*2*2*1 to get 32

6 0
4 years ago
I need help with number 4
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Answer:

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4 0
3 years ago
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Vinil7 [7]
To answer this question we need to find out the nth term
(aka the position-term rule) of this sequence. You'll notice that every term is the previous one multiplied by 2 - it's doubling each time. So we can say that the rule is 2ⁿ, where n is the position of the term in the sequence. Using the laws of exponents, 2ⁿ is equal to 2(2)ⁿ⁻¹. So the answer from the four options is 2(2)ⁿ⁻¹.

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4 0
3 years ago
Use the zero property product to find the solutions to the equation x^2-9= 16
Luba_88 [7]
Subtract 16 to get
  x^2 -25 = 0
Factor this as
  (x -5)(x +5) = 0

The zero product property tells you the product will be zero when one of the factors is zero.

For x-5 = 0
  x = 5

For x+5 = 0
  x = -5

The appropriate choice is
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4 0
3 years ago
An arithmetic progression has first term 11 and Fourth term 32. Fine the sum of the first nine term
schepotkina [342]

Let the first term be a, 4th term be a_{4}, difference between terms be d, and sum of first nine terms be S_{9}.

a_{4} = a + 3d

32 = 11 + 3d

3d = 32 - 11

3d = 21

d = 7

S_{9} = \frac{9}{2} (2a + (9-1)d)

   = \frac{9}{2} (22+56)

   = 9(11+28)

   = 9(39)

   = 325

Sum of first nine terms is 351.

4 0
3 years ago
Read 2 more answers
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