It is possible to arrange the total of mangoes by using 20 piles of 9 mangoes, 18 piles of 10 mangoes, or 15 piles of 12 mangoes.
<h3>What are the different ways the mangoes can be arranged?</h3>
The conditions for mangoes to be arranged are that the piles should have either 9, 10 or 12 mangoes and reminders are not allowed. This means you need to fit all the mangoes and no mangoes can be left.
Based on the conditions and the total number of mangoes (180 mangoes), here are the possibilities that you can determine using division:
- 9 mangoes piles: 180/ 9 = 20 piles (9 x 20 = 180 with no remainders)
- 10 mangoes piles: 180/10 = 18 piles (10 x 18 = 180 with no remainders)
- 12 mangoes piles: 180/12 = 15 piles (12 x 15 = 180 with no remainders)
Learn more about division in brainly.com/question/369266
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This might be wrong but I got 120/1008
The probability of showing a 3 on the first roll is 1/6.
The probability of showing a 3 on the second roll is 1/6.
Because the two rolls are independent events, the probability of showing a 3 on both rolls is
(1/6)*(1/6) = 1/36
Answer: 1/36
Given parameters:
Terms of the sequence = 7/8 , 3/4 , 9/14
From terms, we know that our first term is
We need find either of the common difference or the common ratio of this sequence.
For this, the common ratio is applicable.
Common ratio =
This is the factor by which when we multiply the subsequent terms with results into them;
Solving the above gives
The common ratio is 6/7.
To find the nth of this sequence we apply the formula below;
A = Arⁿ⁻¹
Aₙ is the term we are looking for
A is the first term of the sequence
r is the common ratio
n is the position of the term
So for any nth term in this sequence;
Aₙ = x ⁿ⁻¹
We can use the above solution to find any term in the sequence.