Answer:
possible values of 4th term is 80 & - 80
Step-by-step explanation:
The general term of a geometric series is given by

Where a(n) is the nth term, r is the common ratio (a term divided by the term before it) and n is the number of term
- Given, 5th term is 40, we can write:

- Given, 7th term is 10, we can write:

We can solve for a in the first equation as:

<em>Now we can plug this into a of the 2nd equation:</em>
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</em>
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<em>Let's solve for a:</em>
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</em>
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Now, using the general formula of a term, we know that 4th term is:
4th term = ar^3
<u>Plugging in a = 640 and r = 1/2 and -1/2 respectively, we get 2 possible values of 4th term as:</u>

possible values of 4th term is 80 & - 80
Answer:
The answer is 30 times a year
Step-by-step explanation:
Step-by-step explanation:
Step-by-step explanation:
To answer the question you have t the square of the differences.
So this means that (x-3)^2= x^2-9x+9
Next youmultiply 3 on both sides which says…
x^2-9x+9=27
x^2-9x=18
So, x equals
9/2+3/2 square root 17
OR
9/2-3/2 square root 17
Answer:
the answer is 3465
Step-by-step explanation:
got it right on ed
Answer:

Step-by-step explanation:
we know that
The roots of the quadratic function (x-intercepts) are
x=-1 and x=5/3
so
we can write the equation of the parabola as

where
a is a coefficient
Remember that
The parabola pass through the point (5,40)
substitute the value of x and the value of y of the ordered pair in the quadratic equation and solve for a
x=5, y=40



substitute

apply distributive property

see the attached figure to better understand the problem