We are given two relations
(a)
Relation (R)
![R=[((k-8.3+2.4k),-5),(-\frac{3}{4}k,4)]](https://tex.z-dn.net/?f=R%3D%5B%28%28k-8.3%2B2.4k%29%2C-5%29%2C%28-%5Cfrac%7B3%7D%7B4%7Dk%2C4%29%5D)
We know that
any relation can not be function when their inputs are same
so, we can set both x-values equal
and then we can solve for k







............Answer
(b)
S = {(2−|k+1| , 4), (−6, 7)}
We know that
any relation can not be function when their inputs are same
so, we can set both x-values equal
and then we can solve for k




Since, this is absolute function
so, we can break it into two parts


we get




so,
...............Answer
Answer:
circle and rectangle
Step-by-step explanation:
we know that
A cross section that is perpendicular to the base of cylinder is a rectangle
A cross section that is parallel to the base of cylinder is a circle
A cross section that is angled to the base of cylinder is an oval
Answer:
y=12/x
Step-by-step explanation:
if y=12, and x=1 so
general formula y=12/x
for x=5 , y=12/5=2.4
you can graph by ploting points such as (1,12), (5, 2.4),...