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maksim [4K]
3 years ago
8

In the figure, and bisect each other. Complete the statements to prove that quadrilateral ABCD is a parallelogram.

Mathematics
1 answer:
Alisiya [41]3 years ago
5 0

Observe the figure below.

    Statement                                                                          Reason

1. AC and BD bisect each other                                             Given

2. AE = EC and BE = ED                                                         Definition of bisection

3. m \angle AEB = m \angle CED                       Vertical angle theorem

Vertical angle theorem states " When two lines intersect each other, the vertically opposite angles are always equal".

4. \Delta ABE \cong \Delta CDE                         SAS criterion for congruence

5. m \angle ACD = m \angle CAB           Corresponding angles of congruent triangles are congruent

6. AB \parallel CD                                 Converse of alternate interior angle theorem

7.  m \angle BEC = m \angle AED                   Vertical angle theorem

8.  \Delta BEC \cong \Delta DEA            SAS criterion for congruence

9.  BC \parallel AD                                 Converse of alternate interior angle theorem

As, \Delta BEC \cong \Delta DEA, so m \angle CBD = m \angle BDA as corresponding parts of corresponding triangles are equal. As these angles are alternate interior angles, so the lines BC and AD are parallel by  "Converse of alternate interior angle theorem".

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marshall27 [118]

(2)^3 * (5)^2 * 11

We use PEMDAS so we have to do the exponents first.

2^3 = 8

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You then go left to right cause they are all multiplication:

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Step-by-step explanation:

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Neporo4naja [7]

From the given density function we find the distribution function,

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(a)

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\implies F_{U_1}(u_1)=\begin{cases}0&\text{for }u_1

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(b)

F_{U_2}(u_2)=P(3-Y\le u_2)=P(Y\ge3-u_2)=1-P(Y

\implies F_{U_2}(u_2)=\begin{cases}0&\text{for }u_2

\implies f_{U_2}(u_2)=\begin{cases}\frac32(u_2-3)^2&\text{for }2\le u_2\le4\\0&\text{otherwise}\end{cases}

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F_{U_3}(u_3)=P(Y^2\le u_3)=P(-\sqrt{u_3}\le Y\le\sqrt{u_3})=F_Y(\sqrt{u_3})-F_y(\sqrt{u_3})

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5 0
3 years ago
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amm1812

Answer:

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Step-by-step explanation:

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DochEvi [55]

Answer:

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