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maksim [4K]
3 years ago
8

In the figure, and bisect each other. Complete the statements to prove that quadrilateral ABCD is a parallelogram.

Mathematics
1 answer:
Alisiya [41]3 years ago
5 0

Observe the figure below.

    Statement                                                                          Reason

1. AC and BD bisect each other                                             Given

2. AE = EC and BE = ED                                                         Definition of bisection

3. m \angle AEB = m \angle CED                       Vertical angle theorem

Vertical angle theorem states " When two lines intersect each other, the vertically opposite angles are always equal".

4. \Delta ABE \cong \Delta CDE                         SAS criterion for congruence

5. m \angle ACD = m \angle CAB           Corresponding angles of congruent triangles are congruent

6. AB \parallel CD                                 Converse of alternate interior angle theorem

7.  m \angle BEC = m \angle AED                   Vertical angle theorem

8.  \Delta BEC \cong \Delta DEA            SAS criterion for congruence

9.  BC \parallel AD                                 Converse of alternate interior angle theorem

As, \Delta BEC \cong \Delta DEA, so m \angle CBD = m \angle BDA as corresponding parts of corresponding triangles are equal. As these angles are alternate interior angles, so the lines BC and AD are parallel by  "Converse of alternate interior angle theorem".

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Step-by-step explanation:

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8 0
3 years ago
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rosijanka [135]

Answer:

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Step-by-step explanation:

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Where,

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Plug the values into the formula to find volume.

Volume = \frac{1}{3}*36*\sqrt{7}

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3 years ago
A baseball is thrown in a parabolic arc. It's position above the ground at a given point in time can be represented by the quadr
SCORPION-xisa [38]

Answer:

The baseball reached 9 feet high above the ground

Step-by-step explanation:

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Where;

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g = -32 ft./sec²

v₀ = The initial velocity

p₀ = The initial position

Given that when the ball is thrown, we have;

The initial, straight up, velocity, v₀ = 16 ft./sec

The initial position, p₀ = 5 ft.

Substituting the above values in the quadratic function representing the position of the baseball above ground, we have;

p(t) = 1/2·(-32)·t² + 16·t + 5 = 16·t - 16·t² + 5

At the maximum point, the rate of change of the height with time = 0, therefore;

dp(t)/dt = 0 = d(16·t - 16·t² + 5)/dt = 16 - 32·t

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The height (maximum) reached in 0.5 seconds is given as follows;

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3 years ago
The length of a text messaging conversation is normally distributed with a mean of 2 minutes and a standard deviation of 0.5 min
Hitman42 [59]
Given:
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From standard tables, obtain
P(x ≤ 3) = P(z ≤ 2) = 0.9772
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Answer: 0.02275
8 0
3 years ago
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