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3 years ago

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Mathematics

1 answer:

gogolik [260]3 years ago

5 0

"Linear function" means the highest degree of any term is 1.

Equation 1: degree is 2
Equation 2: degree is 2
Equation 3: degree is 1 . . . . this is your linear function
Equation 4: degree is 4

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A manager at a shipping company will purchase boxes in the shape of right rectangular prisms. He wants the volume of each box to

Archy [21]

Answer:

Step-by-step explanation:

Ok so if u are shipping boxes in a right rectangular prism u will need to either divide or multiply. if he wants to make each box to be exactly 98 cubic feet then he will need to divide so when u do the u will need to find the first part of the answer then u will divide it by 98 cubic feet :> hope u get what i meant

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2 years ago

Matthew changes $770 into rupees. He receives 40 000 rupees.

Yanka [14]

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About 51.94 rupees (rounded).

Step-by-step explanation:

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2 years ago

Nine less than The quotient of two and a number x

aleksley [76]

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2 years ago

Read 2 more answers

Need help with #1 “how is the equation y= 2x similar to the equation y= 2x + 3?how is it different?”

Karo-lina-s [1.5K]

Answer:

The 2nd one would be different from the first because you are adding 3.

Step-by-step explanation:

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2 years ago

The number of bacteria after t hours is given by N(t)=250 e^0.15t a) Find the initial number of bacteria and the rate of growth

Art [367]

Answer:

a) $N_0=250\; k=0.15$

b) 334,858 bacteria

c) 4.67 hours

d) 2 hours

Step-by-step explanation:

a) Initial number of bacteria is the coefficient, that is, 250. And the growth rate is the coefficient besides “t”: 0.15. It’s rate of growth because of its positive sign; when it’s negative, it’s taken as rate of decay.

Another way to see that is the following:

Initial number of bacteria is N(0), which implies $t=0$ . And $N(0)=N_0$ . The process is:

$N(t)=250 e^{0.15t}\\N(0)=250 e^{0.15(0)}\\ N_0=250e^{0}\\N_0=250\cdot1\\ N_0=250$

b) After 2 days means $t=48$ . So, we just replace and operate:

$N(t)=250 e^{0.15t}\\N(48)=250 e^{0.15(48)}\\ N(48)=250e^{7.2}\\N(48)=334,858\;\text{bacteria}$

c) $N(t_1)=4000; \;t_1=?$

$N(t)=250 e^{0.15t}\\4000=250 e^{0.15t_1}\\ \dfrac{4000}{250}= e^{0.15t_1}\\16= e^{0.15t_1}\\ \ln{16}= \ln{e^{0.15t_1}} \\ \ln{16}=0.15t_1 \\ \dfrac{\ln{16}}{0.15}=t_1=4.67\approx 5\;h$

d) $t_2=?\; (N_0→3N_0 \Longrightarrow 250 → 3\cdot250 =750)$

$N(t)=250 e^{0.15t}\\ 750=250 e^{0.15t_2} \\ \ln{3} =\ln{e^{0.15t_2}}\\ t_2=\dfrac{\ln{3}}{0.15} = 2.99 \approx 3\;h$

6 0

2 years ago