Answer:
The probability of selecting a family with exactly one male child is 1/4 or 0.25.
Step-by-step explanation:
Given in the question,
possible outcomes for the children's genders
{FFFF, FFFM, FFMF, FMFF, MFFF, MFFM, MFMF, MMFF, FFMM, FMFM, FMMF, FMMM, MFMM, MMFM, MMMF, MMMM}
= 16
To find,
the probability of selecting a family with exactly one male child
<h3>Probability = favourable outcomes / possible outcomes</h3>
favourable outcomes = {FFFM, FFMF, FMFF, MFFF}
= 4
Probability = 4 / 16
= 1 / 4
= 0.25
Answer:
17
Step-by-step explanation:
4 × 3² = 36
2 × 7 = 14
36 ÷ 12 = 3
3 ± 14 = 17
X equals 53/11 , y equals -16/11
Answer:
7√2 or approx. 9.89949
Step-by-step explanation:
distance between two points is
d=√(∆x^2+∆y^2)
where...
d is distance
∆x is change in x value
and ∆y is change in y value
In this problem ∆x=(-3)-4=(-7)
∆y=5-(-2)=7
plugging in those values gives us
d=√((-7)^2+7^2)
Solving this expression gives us
d=√(49+49)=√98
After simplifying the radical we are left with 7√2 or about 9.89949.
The value of A is 6 and B is 8