Answer:
Step-by-step explanation:
<u>Solve:</u>
- 1 1/2 + 1/4
- = 1/4 + 2 2/3
- = 9/12 + 2 8/12
- = 3 17/12
- = 4 5/12.
Answer is 4 5/12.
4) 121 degrees
because if x is 121 degrees then angle BCA will equal 59 degrees (the two angles must equal 180) so using the sum of a triangle's angles, then angle BAC will have to equal 59, making the triangle an isoceles, which will make AB to be congruent to BC.
Answer:
Point Critical point
Q (2,0) local minimum
R (-2,1) Saddle
S (2,-1) local maximum
T ( -2,-1) Saddle
O ( -2,0) Saddle
Step-by-step explanation: INCOMPLETE ANSWER INFORMATION ABOUT THE POINTS ARE RARE
f(x,y) = x³ +y⁴ - 6x -2y² +3
df/dx = f´(x) = 3x² -6x
df/dxdx = f´´(xx) = 6x
df/dy = f´(y) = -4y
df/dydy = 4
df/dydx = df/dxdy = 0
df/dydy = f´´(yy)
D = [ df/dxdx *df/dydy] - [df/dydx]²
D = (6x)*4 - 0
D = 6*2*4 D > 0 and the second derivative on x is 6*2 = 12
so D > 0 and df/dxdx >0 there is a local minimum in P
Q(2,1)
D = (6*2)*4 D>0 and second derivative on x is 6*2
The same condition there is a minimum in Q
R ( -2,1)
D = 6*(-2)*4 = -48 D< 0 there is a saddle point in R
S (2,-1)
D = 6*2*4 = 48 D > 0 and df/dxdx = 6*-1 = -6
There is a maximum in S
T ( -2,-1)
D = 6*(-2)*(4) = -48 D<0 there is a saddle point in T
O ( -2,0)
D = 6*(-2)*4 = -48 D<0 there is a saddle point in O
It says that the sum of the bases are 46 and the bases are the top and bottom, so that means that one base the top or bottom are 23 each so what do you think
