Answer:
Step-by-step explanation:
The formula for cos θ is a/r. A is the first number (10) and b is the second number (6). R is the hypoteneuse which can be found through r = 
.
In the equation you'd write that as r = 
which can be simplified to 
.
You end up with 
and you simplify this by doing 
, ending with the result of 
.
(I also got this answer right on the test.)
Simplify n + -2 to n - 2
(n - 2)(n + 4) = 27
Expand
n^2 + 4n - 2n - 8 = 27
Simplify n^2 + 4n - 2n - 8 to n^2 + 2n - 8
n^2 + 2n - 8 = 27
Move all terms to one side
n^2 + 2n - 8 - 27 = 0
Simplify n^2 + 2n - 8 - 27 to n^2 + 2n - 35
n^2 + 2n - 35 = 0
Factor n^2 + 2n - 35
(n - 5)(n + 7) = 0
Solve for n
<u>n = 5, -7</u>
Do you remember when you were learning about the "Least Common
Multiple" of two numbers, and you were wondering why you had to learn
it, because you were so sure that you'd never need to use it ? Do you
remember that ?
Well, HERE's where you get to use it. This question is just looking for
the LCM of 6 and 15 . THAT's how many days it will be before you get
homework in both subjects on the same day again.
(It's not 90 days, and it's not 60 days.)
