Setup Fee= $5,500Per CD Charge= $1.00Desired Cost Per CD= $3.50
x= number of CDs
Desired Cost Per CD= Cost per CD + Setup Fee
($3.50 * x)= ($1.00 * x) + $5,500multiply inside parentheses
$3.50x= $1.00x + $5,500subtract $1.00x from both sides
$2.50x= $5,500divide both sides by $2.50
x= 2,200 CDs
ANSWER: x= 2,200 CDs
Hope this helps! :)
The given function is
A . f(4) means we have to evaluate the function when x = 4.
<h2>Therefore, f(4) = 14.</h2>
B. f(x) = 50 means we have to evaluate the function when y = 50.-
<h2>Therefore, f(16) = 50.</h2>
C. f(-5) means we have to evaluate the function when x = -5.
<h2>Therefore, f(-5) = -13.</h2>
D. f(x) = -34.
<h2>Therefore f(-12) = -34.</h2>
Let m = 10 and n = 2
We know:
y^2 = (m+n).m
y^2 = (10+2).10
y^2 = 120
y = √(120)
Then,
m^2 + x^2 = y^2
10^2 + x^2 = ( √( 120) )^2
100 + x^2 = 120
x^2 = 120 - 100
x^2 = 20
x = √(20)
x = √(4×5)
x = √(4) × √(5)
x = 2√(5)
I hope this has helped!
Answer:
(x - 10)(x + 8)
Step-by-step explanation:
x² - 2x - 80
Consider the factors of the constant term (- 80) which sum to give the coefficient of the x- term (- 2)
The factors are - 10 and + 8 , since
- 10 × 8 = - 80 and - 10 + 8 = - 2 , then
x² - 2x - 80 = (x - 10)(x + 8)
The distance between the points (4, 3) and (1, -1) on the coordinate plane will be 5 units. Then the correct option is C.
<h3>What is the distance between two points?</h3>
The shortest distance (length of the straight line segment's length connecting both given points) between points ( p,q) and (x,y) is:
D² = (x - p)² + (y - q)²
The points are given below.
(4, 3) and (1, -1)
Then the distance between the points will be
D² = (4 - 1)² + (3 + 1)²
D² = 3² + 4²
D² = 9 + 16
D² = 25
D = 5 units
Then the correct option is C.
Learn more about the distance between two points here:
brainly.com/question/16410393
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