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Nostrana [21]
3 years ago
14

Kim and leon together have $111. if kim has $17 more than leon, how much does each person have?

Mathematics
2 answers:
aleksandrvk [35]3 years ago
7 0
111-17=94
94/2=47
Leon: $47
Kim: $64
ANTONII [103]3 years ago
6 0
Leon has $47. Kim has $64.
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Help me with elar pls
stiv31 [10]

Answer: indirect characterization

Step-by-step explanation:

Indirect characterization is a method of indicating what a character is like by revealing their personality through descriptions of their actions, speech, appearance, and interactions with other characters.

6 0
3 years ago
Use the simple interest formula method to calculate the future value of an annuity with annual annuity payments of $1200 at 4% i
nikitadnepr [17]

Answer:

Step-by-step explanation:

A = $2,629.35
A = P + I where
P (principal) = $1,200.00
I (interest) = $1,429.35

8 0
2 years ago
michael has a very large soup pot shape like a cylinder that has height of 15 inches and a radius of 6 inches
belka [17]

Answer:

  • 1695.6 in³

Step-by-step explanation:

<em>Cylinder volume formula: V= πr²h</em>

<u>Given</u>

  • h = 15 in
  • r = 6 in

<u>Volume of soup pod</u>

  • V = 3.14*6²*15 = 1695.6 in³
8 0
3 years ago
Find the hypotenuse of each isosceles right triangle when the legs are of the given measure. 6 sqrt 2
Gemiola [76]
Isosceles right triangles have two equal sides (a and b) that are not the hypotenuse (c). And when two sides are equal, so are their opposite angles. There are only 180° degrees in any triangles, thus the right angle = 90°, so 90 left for the two equal, means that 2x=90,
x = 45°.

There are several ways to go about solving a triangle like this. The best and easiest is simply to memorize that the hypotenuse is exactly root2 times the other sides. Or, each isosceles side is the hypotenuse (c) ÷ root2
a = b = c \div  \sqrt{2} \\ c  = a\sqrt{2}  \\ c = 6 \sqrt{2} \times \sqrt{2}  = 6 \times 2 = 12
Another way to do it is the longer proof of Pythagorean Theorem:
{c}^{2}  =  {a}^{2}  +  {b}^{2}... \:  \:  c =   \sqrt{({a}^{2}  +  {b}^{2})}  \\
c= \sqrt{({6 \sqrt{2}) }^{2} + ({6 \sqrt{2})}^{2}}  \\ =  \sqrt{(2 \times{(6 \sqrt{2} )}^{2} )}  =  \sqrt{2(36 \times 2)}  \\ c =  \sqrt{144}  = 12

7 0
3 years ago
Solve for x. 3/x-1 - 1/x^-1=5/x-1<br><br> Please show all work
navik [9.2K]

3/(x-1) - 1/(x^2-1) = 5/(x-1)

Subtract 3/(x-1) from both sides

-1/(x^2-1) = 2/(x-1)

Factor x^2 - 1

-1/[(x-1)(x+1] = 2/(x-1)

Multiply by (x-1)(x+1) on both sides

-1 = 2 (x+1)

-1 = 2x + 2

Subtract 2 from both sides

-3 = 2x

Divide by 2 on both sides

-3/2 = x

5 0
3 years ago
Read 2 more answers
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