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Ivan
4 years ago
9

Help!!!!!!!!!!!!!!!!

Mathematics
1 answer:
Free_Kalibri [48]4 years ago
6 0

Answer:

The solutions the equation 1 are -1.3 and 2. The solutions to equation 2 are -1 and 0.

Step-by-step explanation:

Isolate the absolute value for equation 1. Then, set two equations equal to 5 and -5.

3x - 1 = 5  and   3x - 1 = -5  

Solve for x in both and you would get -1.3 and 2.

Do the same for equation 2.

2x + 1 = -1   and   2x + 1 = 1

Solve for x and you would get -1 and 0.

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Leokris [45]
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4 years ago
Read 2 more answers
Solve. −3/5x +1/5 > 7/20
Reika [66]
-3/5x + 1/5 > 7/20
-3/5x > 7/20 - 1/5
-3/5x > 7/20 - 4/20
-3/5x > 3/20
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3 0
3 years ago
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If b+3/7 = 2/5 then which of the following is true?5b + 15 = 14 b + 3 = 14 5b + 3 = 14 b + 15 = 14
Roman55 [17]

Answer:

The first one is true. 5b+15=14

Step-by-step explanation:

(b+3)/7=  2/5

After cross-multiplication:

5(b+3)=2*7

5b+15=14

5 0
4 years ago
determine an equation and the radius for the circle that has its centre at the origin (0,0) passes through the point A 4-3
g100num [7]

Given:

The center of the circle is at (0,0).

The circle passes through the point A(4,-3).

To find:

The radius and the equation of the circle.

Solution:

Distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

The radius of the circle is the distance between the points (0,0) and (4,-3).

r=\sqrt{(4-0)^2+(-3-0)^2}

r=\sqrt{(4)^2+(-3)^2}

r=\sqrt{16+9}

r=\sqrt{25}

r=5

So, the radius of the circle is 5 units.

The standard form of a circle is

(x-h)^2+(y-k)^2=r^2

Where, (h,k) is center of circle and r is the radius.

Putting h=0, k=0, r=5, we get

(x-0)^2+(y-0)^2=5^2

x^2+y^2=25

Therefore, the radius of the circle is 5 units and the equation of the circle is x^2+y^2=25.

6 0
3 years ago
-6x+y=8<br> 5x+y=8 <br><br> using elimination method
asambeis [7]

Answer:

x=0, y=8. (0, 8).

Step-by-step explanation:

-6x+y=8

5x+y=8

-----------

-6x+y=8

-(5x+y)=-8

--------------

-6x+y=8

-5x-y=-8

-------------

-11x=0

x=0/-11

x=0

5(0)+y=8

0+y=8

y=8-0

y=8

7 0
4 years ago
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