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svp [43]
3 years ago
11

The vertex of this parabola is at (-3,-1). When the y value is 0, the x value is 4. What is the coefficient of the squatted term

Mathematics
1 answer:
kupik [55]3 years ago
5 0
I'm assuming by the way those points lie in the coordinate plane that this is a parabola that opens to the right, a y^2 parabola.  Our x and y coordinates are (4,0), and the h and k of the vertex are (-3, -1).  The standard form for this parabola is x=a(y-k)^2+h.  We need to find a.  Filling in accordingly, 4=a(0+1)^2-3.  Simplifying a bit we get 4 = a - 3.  a = 7.  The parabola, then, has the equation x=7(y+1)^2-3
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Find the value of y when x=3<br> y=2x3<br> y=0
MaRussiya [10]
Answer: 54

Why? You need to put 3 in for x so you get
2(3)^3
3 to the third power is 3*3*3 which equals 27
2(27)
Now you must do 2 times 27 and you get 54

Hope this helps
8 0
3 years ago
What is the probability that a randomly selected graduate has a job if he or she is attending college? Give your answer as
Andrej [43]

Complete question :

Suppose that of the 300 seniors who graduated from Schwarzchild High School last spring, some have jobs, some are attending college, and some are doing both. The following Venn diagram shows the number of graduates in each category. What is the probability that a randomly selected graduate has a job if he or she is attending college? Give your answer as a decimal precise to two decimal places.

What is the probability that a randomly selected graduate attends college if he or she has a job? Give your answer as a decimal precise to two decimal places.

Answer:

0.56 ; 0.60

Step-by-step explanation:

From The attached Venn diagram :

C = attend college ; J = has a job

P(C) = (35+45)/300 = 80/300 = 8/30

P(J) = (30+45)/300 = 75/300 = 0.25

P(C n J) = 45 /300 = 0.15

1.)

P(J | C) = P(C n J) / P(C)

P(J | C) = 0.15 / (8/30)

P(J | C) = 0.5625 = 0.56

2.)

P(C | J) = P(C n J) / P(J)

P(C | J) = 0.15 / (0.25)

P(C | J) = 0.6 = 0.60

5 0
2 years ago
Please help me with this
zhenek [66]
1A
2C
3A
4D
5D
6C
7B
8A
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10D
8 0
3 years ago
Can someone simplify pls
algol [13]

we are given to simplify

\\ \ (x^6y^5)(5xy^2)(-6x^4)\\ \\

Open the bracket and write the like terms together

\\ \ =x^6y^5*5xy^2*(-6)x^4\\ \\ \ =-30x^6*x*x^4*y^5*y^2\\ \\

when the bases are same then the exponents gets added

\\ \ =-30x^{6+1+4}y^{2+5}\\ \\ \ =-30x^{11}y^7

8 0
3 years ago
Read 2 more answers
Write the equation of the line whose slope and the point through which it passes are
sveticcg [70]

Answer:

y+4=6(x+7)

Step-by-step explanation:

y-y1=m(x-x1)

y-(-4)=6(x-(-7))

y+4=6(x+7)

4 0
2 years ago
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