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4 years ago

11

Mr.Tan and his friends planned a group visit for three adults and nine children.Find the amount of money they had to pay for the

ir tickets. Per adult$12.Per child $8

1 answer:

siniylev [52]4 years ago

7 0

$36 for adults, $56 children.

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Find the area of the following parallelogram:

nalin [4]

Answer:

216

Step-by-step explanation:

18 which is the base will be multiplied by the height which is 12 giving you

18 x 12 = 216

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3 years ago

Help me out please. Correct answers only

Sergio [31]

Answer:

c=39

Step-by-step explanation:

4+2=6

To remove square root you have to square everything making the 6 a 36 and then add 3. At the end it is a 39.

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3 years ago

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What is 4 x 8 = 16 +

Rudiy27

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Find the average value of f(x+y)=sin(x+y) over

Troyanec [42]

For each given region $D$ , the average value of $f$ over $D$ is the integral of $f$ over $D$ divided by the area of $D$ . In both cases, $D$ is a rectangle so the area is trivial.

a. The area of $D$ is $\dfrac\pi3\cdot\dfrac{5\pi}3=\dfrac{5\pi^2}9$ . The integral of $f$ over $D$ is

$\displaystyle\int_0^{5\pi/3}\int_0^{\pi/3}\sin(x+y)\,\mathrm dx\,\mathrm dy$

$\displaystyle=\int_0^{5\pi/3}\left(\cos y-\cos\left(y+\dfrac\pi3\right)\right)\,\mathrm dy$

$=\sin\dfrac{5\pi}3-\sin\left(\dfrac{5\pi}3+\dfrac\pi3\right) - \sin0+\sin\dfrac\pi3=0$

So the average value of $f$ over this region is 0.

b. The area of $D$ is $\dfrac{2\pi}3\cdot\dfrac{7\pi}6=\dfrac{7\pi^2}9$ . The integral of $f$ is

$\displaystyle\int_0^{7\pi/6}\int_0^{2\pi/3}\sin(x+y)\,\mathrm dx\,\mathrm dy$

$=\displaystyle\int_0^{7\pi/6}\left(\cos y-\cos\left(y+\frac{2\pi}3\right)\right)\,\mathrm dy$

$=\sin\dfrac{7\pi}6-\sin\left(\dfrac{7\pi}6+\dfrac{2\pi}3\right) - \sin0+\sin\dfrac{2\pi}3=\dfrac{\sqrt3}2$

The average vale of $f$ over this region is then $\dfrac{\frac{\sqrt3}2}{\frac{7\pi^2}9}=\dfrac{9\sqrt3}{14\pi^2}$ .

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3 years ago

56868×677433576432answer the question please I am running out of time

Papessa [141]

3.825242926*10^16 is the answer.

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3 years ago