k is the shift up and down
so to shift it down K < 0
h is the shift left and right
a positive shifts left
h>0
Choice C
R = { (x,y): 3x-y=0 }
The condition is 3x=y so that's not going to be any of these things.
R is reflexive if (x,x)∈R for all x. Let's check.
3x - y = 3x - x = 2x ≠ 0 necessarily. NOT REFLEXIVE
R is symmetric if (x,y)∈R → (y,x)∈R. Let's check.
(x,y)∈R so
3x-y = 0
y = 3x
Is (y,x)∈R. That would be true if 3y-x=0
3y - x = 3(3x) - x = 8x ≠ 0 necessarily NOT SYMMETRIC
R is transitive if (x,y)∈R and (y,z)∈R → (x,z)∈R. Let's check.
3x-y = 0 so y=3x
3y-z = 0 so z=3y = 9x
3x - z = 3x - 9x = -6x ≠ 0 necessarily NOT TRANSITIVE
Answer:
Step-by-step explanation:
I suppose the expression is this 
We can factor out this expression ( Remember, find two numbers that the sum is 9 and the product is 8. The numbers are 8 and 1)

Step-by-step explanation:
this is the answer in the picture
Check the picture below.
so the lateral area will be just the area of the sides, namely excluding the bases at top and bottom, thus
