We have been given graph of a downward opening parabola with vertex at point 
. We are asked to write equation of the parabola in standard form.
We know that equation of parabola in standard form is 
.
We will write our equation in vertex form and then convert it into standard form.
Vertex for of parabola is 
, where point (h,k) represents vertex of parabola and a represents leading coefficient.
Since our parabola is downward opening so leading coefficient will be negative.
Upon substituting coordinates of vertex and point (0,0) in vertex form, we will get:
Divide both sides by 
So our equation in vertex form would be 
.
Let us convert it in standard from.
Therefore, the equation of function is standard form would be .
In an isosceles triangle, the base angles are congruent. The third angle is called the vertex angle.
Here, the vertex angle is <A.
Therefore, m<C = m<B.
m<A = 3m<B + 20
m<A + m<B + m<C = 180
3m<B + 20 + m<B + m<B = 180
5m<B + 20 = 180
5m<B = 160
m<B = 32
m<C = m<B = 32
Answer: m<C = 32 deg
Answer:
21
Step-by-step explanation:
3x-7=-21
-21x-1=21
hope this helps, brainliest is always appreciated :3
The answer is 11
Explaination:
9/14 multiple both numbers by 3=27/42
Break 2 1/3 into 2 and 1/3
1/3 multiple both numbers but 14=14/42
27/42 x 14/42 keep number on the bottom the same
27x14= 378
Divide 378/42=9
Add the 2 from 2 1/3 to the nine
2+9=11
