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andreyandreev [35.5K]
3 years ago
12

2x%___=256%___ X=______

Mathematics
1 answer:
kykrilka [37]3 years ago
3 0
(2x)/2= (256)/2
X=128
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The veterinarlan told Sally that her cat needs to lose 5 pounds. A healthy weight loss for her cat would be about 1 pound every
padilas [110]

Answer:

It would take 10 weeks for her cat to lose 5 pounds.

Step-by-step explanation:

4 0
2 years ago
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Let g(x)=x-3 and h(x)=x^2+6 find (h o g) (1)
cupoosta [38]
g(x)=x-3 \ \ \ and\ \ \  h(x)=x^2+6 \\\\(h \circ  g) (1)=h\bigg (g(1)\bigg)=h\bigg(1-3\bigg)=h(-2)=(-2)^2+6=4+6=10
5 0
3 years ago
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Hansen won the raffle At the zoo and gets to feed the dolphins! The dolphin trainer gives Hansen a bucket of fish to divide even
Pachacha [2.7K]

Answer:

Number of dolphins in zoo * number of fish per dolphin.

Step-by-step explanation:

Hansen won the raffle At the zoo and gets to feed the dolphins! The dolphin trainer gives Hansen a bucket of fish to divide evenly among five dolphins. Each dolphin gets four fish. Which equation can you use to find the number of fish F in the bucket before hansen feeds them

Given that:

Number of dolphins = 5

Fish in bucket is distributed equally ; hence, Number of fish per dolphin = 4

To obtain the initial number of fish in bucket before hansen began to feed the fishes :

Number of fish in bucket before hansen feeds then :

Number of dolphins in zoo * number of fish per dolphin.

5 * 4 = 20

6 0
3 years ago
Expansion Numerically Impractical. Show that the computation of an nth-order determinant by expansion involves multiplications,
posledela

Answer:

  • number of multiplies is n!
  • n=10, 3.6 ms
  • n=15, 21.8 min
  • n=20, 77.09 yr
  • n=25, 4.9×10^8 yr

Step-by-step explanation:

Expansion of a 2×2 determinant requires 2 multiplications. Expansion of an n×n determinant multiplies each of the n elements of a row or column by its (n-1)×(n-1) cofactor determinant. Then the number of multiplies is ...

  mpy[n] = n·mp[n-1]

  mpy[2] = 2

So, ...

  mpy[n] = n! . . . n ≥ 2

__

If each multiplication takes 1 nanosecond, then a 10×10 matrix requires ...

  10! × 10^-9 s ≈ 0.0036288 s ≈ 0.004 s . . . for 10×10

Then the larger matrices take ...

  n=15, 15! × 10^-9 ≈ 1307.67 s ≈ 21.8 min

  n=20, 20! × 10^-9 ≈ 2.4329×10^9 s ≈ 77.09 years

  n=25, 25! × 10^-9 ≈ 1.55112×10^16 s ≈ 4.915×10^8 years

_____

For the shorter time periods (less than 100 years), we use 365.25 days per year.

For the longer time periods (more than 400 years), we use 365.2425 days per year.

8 0
3 years ago
Using the graph as your guide, complete the following statement.
ollegr [7]

Answer:

positive

Step-by-step explanation:

the discriminant of the function is postive.

because from the graph we notice that it has 2 intercepts on x-axis, which means the function has 2 real solution when y=0

that implies the discriminant is positive.

\Delta = \sqrt{b^2-4ac}

if \Delta > 0 we have 2 distinct real solution

if \Delta we have no real solution but 2 complex solutions

if \Delta = 0 we have 2 identical real solution

7 0
3 years ago
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