Using the normal distribution, there is a 0.4826 = 48.26% probability that the sample mean is between 15 and 16 grams per day.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:

- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
- By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation
.
For this problem, the parameters are given as follows:

The probability is the <u>p-value of Z when X = 16 subtracted by the p-value of Z when X = 15</u>, hence:
X = 16:

By the Central Limit Theorem


Z = 2.11
Z = 2.11 has a p-value of 0.9826.
X = 15:


Z = 0
Z = 0 has a p-value of 0.5.
0.9826 - 0.5 = 0.4826 = 48.26% probability that the sample mean is between 15 and 16 grams per day.
More can be learned about the normal distribution at brainly.com/question/15181104
#SPJ1
X=120
This is the answer because 120-21=99
9514 1404 393
Answer:
yes, it is a function
Step-by-step explanation:
A graph represents a functional relationship if no vertical line intersects the graph in more than one point. A horizontal line passes this "vertical line test," so represents a function.
Answer:
If there are 1000 customers in the store one week, how many will purchase exactly one of these items
1000 CUSTOMERS*28%=280
Step-by-step explanation:
A The event that a persons buys a suit
B The event that a person buys a shirt
C The event that a person buys a tie
P(A)= 22%
P(B)= 30%
P(C)= 28%
P(AB)=
11%
P(AC)=
14%
P(BC)=
10%
P(ABC)=
6%
A u B u C Is the event that any item is bougth
AC u AC u BC Is the event that any two events occured
So the wanted probability is
P[(A u B u C )(AB u AC u BC)^c
P[(A u B u C )=P(AB)+ P(BC)+P(BC)
P[(A u B u C ) =0.22+0.30+0.28-0.11-0.14.-0.10+0.06
=0,51
0,51=+0,23+P[(A u B u C )(AB u AC u BC)^c
=0,28
1000 CUSTOMERS*28%=280
She sold 2592 pears. If 2592/3=864 then when the total of pears and apples are added it should equal 3,456
2592+864=3456