Answer:
Part 1
Type II error
Part 2
No ; is not ; true
Step-by-step explanation:
Data provided in the question
Mean = 100
The Random sample is taken = 43 students
Based on the given information, the conclusion is as follows
Part 1
Since it is mentioned that the classes are successful which is same treated as a null rejection and at the same time it also accepts the alternate hypothesis
Based on this, it is a failure to deny or reject the false null that represents type II error
Part 2
And if the classes are not successful so we can make successful by making type I error and at the same time type II error is not possible
Therefore no type II error is not possible and when the null hypothesis is true the classes are not successful
Answer:
23
Step-by-step explanation:
i think i hope it help
Answer:
470(32-n)
Step-by-step explanation:
Answer:
150/250
Step-by-step explanation:
24/42, 75/135, 150/250, and 75/150 I believe is what you're asking. We know 75/135 is better than 75/150 so 75/150 is out of the equation. If we multiple 75/135 by 2 we get 150/270 which is more than 150/250, so 75/135 is out of the equation. Now to compare 24/42 and 150/250 we can divide their fractions, if we divide 24/42 we get 0.57, so 57%. If we did 150/250 we get 0.6 or 60%. So 150/250 is the best score.
Answer:
It is a many-to-one relation
Step-by-step explanation:
Given
See attachment for relation
Required
What type of function is it?
The relation can be represented as:
![\left[\begin{array}{c}y\\ \\10\\11\\4\\10\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dy%5C%5C%20%5C%5C10%5C%5C11%5C%5C4%5C%5C10%5Cend%7Barray%7D%5Cright%5D)
Where
and 
Notice that the range has an occurrence of 10 (twice)
i.e.
and 
In function and relations, when two different values in the domain point to the same value in the range implies that, <em>the relation is many to one.</em>