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zhuklara [117]
4 years ago
5

PQ=6x+25 and QR = 16-3

Mathematics
1 answer:
alexgriva [62]4 years ago
8 0
6x+25 + 16 - 3x =
3x + 41 that is my answer if not I try to help you
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Maddie spent $76 on shoes. That is 43% of her savings account. What is was the total amount of Maddie's savings account before p
marishachu [46]

Answer:

The total saving =$ 176.64

Step-by-step explanation: let Maddie's saving amount be x.

Maddie spent = $76 maddie spent in percent = 43%

We know, 43% of x = $76 or, 0.43x = $76 or, x = $76/0.43 or, x = $176.74

total savings = $176.74

6 0
4 years ago
Express this in scientific notation 90,000
SSSSS [86.1K]
9 times 10 to the 4th power
8 0
3 years ago
What is the interquartile range of 2 5 9 11 18 30 42 55 58 73 81
Eva8 [605]

Answer:

49.

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Find the slope of the line that passes through (-6, -2) and (-7, -2)
Jobisdone [24]

Answer:

0

Step-by-step explanation:

We could use the Slope Formula to find the answer, but there's an easier way of doing it. Notice that the y-coordinates of both points are the same. This means that the line that passes through these points is horizontal, which makes our answer 0 because all horizontal lines have a slope of 0.

All horizontal lines have a slope of 0 because the value of y never changes as the value of x changes, so if we were to input any two points on a horizontal line into the Slope Formula, our numerator would be 0 (because anything subtracted from itself is 0), leaving us with a result of 0 regardless of the denominator since 0 divided by anything is 0. Hope this helps!

6 0
3 years ago
Two forces with magnitudes of 150 and 100 pounds act on an object at angles of 30° and 120°, respectively. Find the direction an
lyudmila [28]
<h2>Answer:</h2>

Magnitude=180.27 \ lbf \\ \\ Direction=63.69 \ degrees

<h2>Step-by-step explanation:</h2>

We have two forces as follows:

<u>First force:</u>

Magnitude: 150 pounds

Angle: 30°


<u>First force:</u>

Magnitude: 100 pounds

Angle: 120°


So the components can be found as follows:

F_{1x}=150cos(30)=129.90 \ lbf\\F_{1y}=150sin(30) = 75 \ lbf \\ \\ F_{2x}=100cos(120)=-50 \ lbf\\F_{2y}=100sin(120) = 86.60 \ lbf


So the components of the resultant force can be found by adding each component of the individual forces as follows:

R_{x}=\Sigma F_{x} \\ R_{y}=\Sigma F_{y} \\ \\ R_{x}=129.90-50=79.90 \ lbf \\ R_{y}=75+86.60=161.6 \ lbf


Finally, the magnitude and direction of the resultant force is:

Magnitude \rightarrow R=\sqrt{R_{x}^2+R_{y}^2}=\sqrt{79.90^2+161.6^2}=180.27 \ lbf \\ \\ Direction \rightarrow \theta=tan^{-1}(\frac{R_{y}}{R_{x}})=tan^{-1}(\frac{161.6}{79.90})=63.69 \ degrees

6 0
3 years ago
Read 2 more answers
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