Answer:
A two-step equation is something like:
A*X + B = C
In this case, like in a linear equation, we have only one solution that can be found as:
A*X = C - B
X = (C - B)/A
In the case of a two-step inequality, we have something like:
A*X + B > C
Solving this we get;
A*X > C - B
X > (C - B)/A
In this case, any value of X that is larger than (C - B)/A is a solution, so in this case, we have infinite solutions.
That is the difference between the number of solutions for each case, in a two-step equation we have only one, while in the case of the inequality we have infinite.
The nearest whole number is 11 and the nearest tenth is 11.4. So your answer is 11.4
Answer:
The best fit is <em>A. Linear model</em>
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Step-by-step explanation:
Given:
Monthly Rate = $20, Number of customers = 5000
If there is a decrease of $1 in the monthly rate, the number of customers increase by 500.
To find:
The type of model that best fits the given situation?
Solution:
Monthly Rate = $20, Number of customers = 5000
Let us decrease the monthly rate by $1.
Monthly Rate = $20 - $1 = $19, Number of customers = 5000 + 500 = 5500
Let us decrease the monthly rate by $1 more.
Monthly Rate = $19 - $1 = $18, Number of customers = 5500 + 500 = 6000
Here, we can see that there is a <em>linear change </em> in the number of customers whenever there is decrease in the monthly rate.
We have 2 pair of values here,
x = 20, y = 5000
x = 19, y = 5500
Let us write the equation in slope intercept form:
Slope of a function:
So, the equation is:
Putting x = 20, y = 5000:
Let us check whether (18, 6000) satisfies it.
Putting x = 18:
so, it is true.
So, the answer is:
The best fit is <em>A. Linear model</em>
Answer:
8 hours
$480
Step-by-step explanation:
Let us assume the hours be x
There should be two equations
For Plumber A = 60x
For Plumber B = 40 + 55x
Now in order to considered the cost to be the same we equate these two equations
60x = 40 + 55x
5x = 40
x = 8 hours
Now the total cost for plumber A is
= 480
And, the total cost for plumber B is
= 40 + 55(8)
= 480
hence, the total cost is $480
Given:
JKLM: J(8,4) ; K(4,10) ; L(12,12) ; M(14,10)
I'll just use the first vertex of every quadrilateral in comparison with J(8,4)
A(-8,-4) ; B(-4,-10) ; C(-12,-12) ; D(-14,-10) → a sequence of reflections across the x and y-axes, in any order. This is easy because each vertex has the same number but different signs.
E(11,2) ; F(7,8) ; G(15,10) ; H(17,8) → a translation of 3 units left and 2 units up. As you can envision with a graph, from 11 to 8, you need to move to the left of the x-axis. from 2 to 4, you need to move up of the y-axis.
O(6,7) ; P(2,13) ; Q(10,15) ; R(12,13) → a translation 2 units right and 3 units down. From 6 to 8 of the x-axis and from 7 to 4 of the y axis.
S(4,16) ; T(10,20) ; U(12,12) ; V(10,10) → This one has no pair but it seems as though this is rotated along the point U.
W(11,7) ; X(7,13) ; Y(15,15) ; Z(17,13) → a translation 3 units down and 3 units left.
