PQ=6x+25 and QR = 16-3
1 answer:
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Hello and Good Morning/Afternoon:
<u>Let's take this problem step-by-step:</u>
<u>First off, let's write the line in point-slope form:</u>
- (x₀, y₀) any random point on the line
- 'm' is the value of the slope
<u>Let's calculate the slope:</u>
- (x₁, y₁): any random point on the line ⇒ (-2, -6)
- (x₂,y₂): any random point on the line that is not (x₁, y₁) ⇒ (2, -3)
<u>Now that we found the slope, let's put it into the point-slope form</u>
⇒ we need (x₀, y₀) ⇒ let's use (2,-3)
<u>The equation, however, could also be put into 'slope-intercept form'</u>
⇒ gotten by isolating the 'y' variable to the left
<u>Answer:</u> or
*<em>Either equations work, put the one that you are the most familiar with</em>
Hope that helps!
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