Answer:
0.166666667, to round up it is 0.17
Step-by-step explanation:
Answer:
293.38 pounds
Step-by-step explanation:
We are given that
Distance between poles=35 feet

Weight of cable=10.4 per linear foot
We have to find the weight of the cable.
Differentiate w.r.t




Let 


![s=\frac{2}{0.0225}\times\frac{2}{3}[t^{\frac{3}{2}}]^{17.5}_{0}](https://tex.z-dn.net/?f=s%3D%5Cfrac%7B2%7D%7B0.0225%7D%5Ctimes%5Cfrac%7B2%7D%7B3%7D%5Bt%5E%7B%5Cfrac%7B3%7D%7B2%7D%7D%5D%5E%7B17.5%7D_%7B0%7D)
![s=2\times \frac{2}{3\times0.0225}[(1+0.0255x)^{\frac{3}{2}]^{17.5}_{0}](https://tex.z-dn.net/?f=s%3D2%5Ctimes%20%5Cfrac%7B2%7D%7B3%5Ctimes0.0225%7D%5B%281%2B0.0255x%29%5E%7B%5Cfrac%7B3%7D%7B2%7D%5D%5E%7B17.5%7D_%7B0%7D)

s=28.21
Weight of cable=
pound
Answer:
37°
Step-by-step explanation:
we're going to use cosine rule In calculating for the value of angle A
note that cosine rule can be used when two sides are given with an included angle . from the diagram above, the two sides given are side AB and side AC and the included angle is A
Hence cosine rule
a^2 = AB^2+AC^2 - 2AB×AC Cos A
3.2^2= 2.1^2+4.6^2-2×2.1×4.6COSA
10.24 =4.41+21.16- 19.32 COSA
10.24 = 25.57-19.32COSA
10.24-25.57= -19.32COSA
-15.33= -19.32COSA
dividing bothsides by - 19.32
COSA= -15.33/19.32
COA= 0.79347826
A = COS^-1 (0.79347826)
A= 37.488
A= 37°
<h2>hope this helps!!</h2>
Answer:
first of all,
Step-by-step explanation:
In triangle ABC one side equal and two sides equal
Step-by-step explanation:
We are given a prism whose base is square with sides 8 in and height 12 in.
If we take cross section through vertices A, B and C
We will get a cross section as triangle.
In triangle ABC, sides are AB, BC and AC
AB is diagonal of top square whose side 8 in.
AC is face diagonal of front face.
BC is face diagonal of right face.
AC=BC≠AB
Hence, In triangle ABC one side equal and two side equal
Hope this helps!!