Charge q is 1 unit of distance away from the source charge S. Charge p is two times further away. The force exerted between S and q is _____ the force exerted between S and p
a. 1/2
b. 2 times
c. 1/4
d. 4 times
Answer:
4 times
Step-by-step explanation:
Given the following :
Distance between q and S (r) = 1 unit
Distance between P and S (r) = 2 × 1 unit = 2
According to coliumbs law:
F = Ke(q1q2) /r^2
Where F = electrostatic force, Ke = coloumbs constant
q1,q2 = charges, r = distance between two charges
For q and S :
Fsq = Ke(q1q2) / 1^2
Fsq = Ke(q1q2) - - - - - equation 1
For P and S :
Fsp = Ke(q1q2) / 2^2
Fsp = Ke(q1q2) / 4 - - - - - equation 2
Dibiding equation 1 by equation 2
Fsq/Fsp = Ke(q1q2) / Ke(q1q2)/4
Fsq / Fsp = Ke(q1q2) × 4 / Ke(q1q2)
Fsq / Fsp = 4 / 1
Using cross multiplication
Therefore, Fsq = 4 × Fsp
Answer:
GG from Shahs I am not a good time to meet you and your company and the other side of the year and the other hand the year and a good time and money by simply beautiful day in the future of our lives to the other hand I
Answer: 17x+9
Step-by-step explanation:
The mean is the same thing as the average. To find the average, add all the numbers up (aka find the sum of the numbers) and divide by how many numbers there is:
So the sum of your numbers is: -6 + 2 + 5 + -7 + -11 + -6 = -23. And there are 6 numbers total.
That means average =
≈ -3.8
Your final answer is -3.8
Answer:
3.033
Step-by-step explanation:
5.21*7.3=3.003
