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Kamila [148]
2 years ago
11

URGENT! PLEASE HELP

Mathematics
1 answer:
olga2289 [7]2 years ago
3 0

Answer:

Answer: 0.005523 kilometer = 5.52 meter In this case, you are asked how much the water height and given the water volume ( 1.9 million cubic kilometers) and the earth area (344milion square kilometers). To answer this question you just need to divide the volume with the area.

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Aaron made a picture frame with the dimensions shown in the figure. What is the area of the picture frame? 120 square centimeter
Temka [501]
72 square centimeters because 
<span>(12×10)−(8×6)</span>
<span>120−48</span>
<span>72</span>
7 0
3 years ago
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4(3x+2y) distributive property pls help
Sonbull [250]

Answer:

12x+8y

Step-by-step explanation:

1) Expand by distributing terms.

4*3x+4*2y

2) Simplify 4*3x to 12x.

12x+4*2y

3) Simplify  4*2y to 8y.

12x+8y

<u>Therefor, the answer is </u><u>12x + 8y.</u>

8 0
2 years ago
Just an answer and simple explanation! Thank you.
vazorg [7]

Answer:

15

Step-by-step explanation:

If CD and DE equal, then x+6 = 4x -21

So if you subtract x from both sides and plus 21 to both sides, that would be 3x = 27. Divide by 3 on both sides and you get 9.

Plug in x+6 with 9 and you get 15.

6 0
2 years ago
You are in a hot air balloon looking down at two ponds. Pond A which is in front of your balloon, is at an angle of depression t
MatroZZZ [7]

a. See attachment for the labelled diagram

b. Using the sine ratio, distance from the hot air to pond A is 5,038.9 m, while distance from the hot air to pond B is 6,287.1 m.

c. Distance between the two ponds is 1,263.5 m.

<h3>What is the Sine and Tangent Ratios?</h3>

Sine ratio, is: sin ∅ = opposite side/hypotenuse length

Tangent ratio is: tan ∅ = opposite side/adjacent length.

a. The diagram with the appropriate labels is shown in the image attached below.

b. Use the sine ratio to find the distance from the hot air to pond A (CA) and to pond B (CB):

CA = hypotenuse

∅ = 10°

Opposite = 875 m

sin 10 = 875/CA

CA = 875/sin 10

CA ≈ 5,038.9 m (distance from the hot air to pond A)

CB = hypotenuse

∅ = 8°

Opposite = 875 m

sin 8 = 875/CB

CB = 875/sin 8

CB ≈ 6,287.1 m (distance from the hot air to pond B)

c. Distance between the two ponds, BA = BD + DA.

Apply the tangent ratio to find BD and DA

tan 8 = 875/BD

BD = 875/tan 8

BD = 6,225.9 m

tan 10 = 875/DA

DA = 875/tan 10

DA = 4,962.4 m

Distance between the two ponds = 6,225.9 - 4,962.4 = 1,263.5 m.

Learn more about the sine and tangent ratios on:

brainly.com/question/24137232

#SPJ1

8 0
2 years ago
Picture above please solve
Y_Kistochka [10]

Answer:

1) 3x(3x-1)

2)5(9x^2-3x+1)

6 0
3 years ago
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