H'(x) = 2f'(x)
h'(1) = 2*f'(1) = 2*4
h'(1) = 8
Givens
<em><u>Slower car</u></em>
r = r
t = 12 hours
d = ?
<em><u>Faster car</u></em>
r = r + 20
t = 8 hours
d = ?
It doesn't matter what the exact distance is. You just have to know that the 2 distances are equal ie going to the mountains from his home is the same distance as going from the mountains to his home.
d = r * t
r * 12 hours = (r + 20)* 8 hours. Remove the brackets on the right
r*12 = 8r + 20*8
r*12 = 8*r + 160
r*12 - 8r = 8r - 8r + 160
4r = 160
r = 40 miles / hour
=================
Slower Ride determines the distance.
d = r*t
d = 40 * 12
d = 480
Check
Use the faster rate (r + 20) = 40 + 20 = 60 mph
60 * 8 = 480. Both distances work out to be the same.
Answer:
A. O 5
Step-by-step explanation:
1830 ÷ 31 = 59.032258...
The first non-zero digit of the quotient is 5.
Answer:
145 yd²
Step-by-step explanation:
There will be dour triangular faces. For a triangle, area is given as
A=½bh where b is base and h is height. The base will be 5 yards and h is 12 yards hence for one triangular face, area will be ½*5*12=30 yd²
Since they are four similar triangles, area of triangular faces will be 30*4=120 yd²
The surface area of a square base is given by
A=a*a=a² where a is the dimension of one side. Given that the meaurement is 5 yards then A=5²=25 yd²
Total area will be the sum of triangular and square faces hence 120+25=145 yd²
Answer:
The answer in the procedure
Step-by-step explanation:
Let
x----> the first number
y----> the second number
we know that
so
-----> equation A
----> equation B
substitute equation A in equation B
