Question

The graph of which of the following functions has a vertex at (4, -3)?

Answer 1

Answer:

Therefore the answer is the fourth option y = f(x) = $x^{2}$  - 8x + 13

Therefore when x = 4 then y = -3 from the equation of parabola and this is the required vertex.

Step-by-step explanation:

i) f(x) = $x^{2}$ + 8x + 19    =  $(x + 4)^{2}$ + 3. SO the vertex is at (-4, 3)

Therefore the answer is the fourth option y = f(x) = $x^{2}$  - 8x + 13

 = ($x^{2}$  - 8x + 16) + 3  = $(x-4)^{2}$ - 3

Therefore when x = 4 then y = -3 from the equation of parabola and this is the required vertex.