Hello,
For a given perimeter (P) there are an infinity of Area (A)
Let's say x the length, and y the wide of the rectangle
P=2(x+y)
A=xy
k=x-y >=0
As (x+y)²-4xy=(x-y)²: A²-4P=k² or P=(A²-k²)/4
In primus, you will find a graph (abacus) giving P for a A and k given.
Negative Area or P are excluded.(just remind the first quadrant, A>=0 and P>=0)
Answer:
x = 3/8 +/- i(√5)/8.
Step-by-step explanation:
I can't see any list by this is the solution of the equation:
x^2 - 3/4x = -1/4
x^2 - 3/4 x + 1/4 = 0
Multiply by 4 to remove the fractions:
4x^2 - 3x + 1 = 0
x = [-(-3) +/- sqrt(3)^2 - 4*4*1)] / 8
x = 3/8 +/-√ (-5) / 8
x = 3/8 +/- √5 i / 8
Answer:
Step-by-step explanation:
The area of a triangle is:
A=05*b*h
b= base = x
h = height = x-12
A = (1/2)(x)(x-12)
You mean what is 9/0 simplified to?