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Leni [432]
3 years ago
10

NEED HELP ASAP 60 POINTS AND WILL MARK AS BRAINLIEST Alex, an eighth grader, and Eric, a seventh grader, need to determine who c

ame closer to their grade’s state record for the triple jump. Alex jumped 39.85 feet and Eric jumped 37 feet and "1" "1" /"4" inches. Who was closer to the state record if the eighth-grade record is 42.25 feet and the seventh-grade record is 39 feet 3 inches?
Mathematics
2 answers:
Helga [31]3 years ago
5 0
42.25-39.85=2.4
37+1 1/4= 38.25
39.25-38.25=1
Eric came closer. Hope this helps!
Lesechka [4]3 years ago
3 0

Answer:

Eric was closer to the state record.

Step-by-step explanation:

Consider the provided information.

Alex jumped 39.85 feet the eighth-grade record is 42.25 feet.

Let see how closer Alex jumped was.

42.25 -39.85=2.4

Eric, a seventh grader, and he jumped 37 feet and "1" "1" /"4" inches. The seventh-grade record is 39 feet 3 inches.

First convert 37 feet and "1" "1" /"4" inches into feet.

1\frac{1}{4}=\frac{5}{4}

1\ in=0.083\ foot

Multiply both sides by 5/4.

\frac{5}{4}\ in=0.104167\ foot

That means total distance was 37+0.104167=37.104167 feet.

seventh-grade record is 39 feet 3 inches.

3 in = 0.25 foot

Therefore, the seventh grade record is 39+0.25=39.25 feet

39.25-37.104167=2.145833

2.145833 is smaller than 2.4

Hence, Eric was closer to the state record.

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