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Likurg_2 [28]
4 years ago
7

Evaluate for x = 2 and y = 3 x^2y^-3/x^-1y

Mathematics
1 answer:
Tasya [4]4 years ago
6 0
First plug them all in for 2^6^-3/2^-3

Then solve to get. 134217728
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What is the decision regarding the differences between the observed and expected frequencies if the critical value of the chi-sq
ra1l [238]

Answer:

Accept the null hypothesis if it is two tailed test.

Step-by-step explanation:

The null hypotheses can only be accepted if it is a two tailed test and calculated chi square must be less than the critical value of chi square.

Then the difference between the  the observed and expected frequencies will be zero.

where

H0 : σ²-σ²= 0             Ha: σ²-σ²≠0

For this the critical region would be greater than the calculated value of chi square. If so we will accept the null hypothesis and reject the alternative hypothesis.

4 0
3 years ago
Find the factor of the polynomial.
hichkok12 [17]
Its the third one down
8 0
3 years ago
Read 2 more answers
Pls help in a middle of an exam
KIM [24]

Answer:

\frac{2x^2+4x-9}{(2x-3)(2x+3)(x-1)}

Step-by-step explanation:

\frac{2x}{4x^2-9} + \frac{3}{2x^2+x-3} can be simplified to:
\frac{2x}{(2x-3)(2x+3)}+\frac{3}{(2x+3)(x-1)}

Make them have common denominators so:
\frac{(2x)(x-1) +3(2x-3)}{(2x-3)(2x+3)(x-1)}

Simplify:
\frac{2x^2-2x+6x-9}{(2x-3)(2x+3)(x-1)} = \frac{2x^2+4x-9}{(2x-3)(2x+3)(x-1)}

I don't think you can simplify that fraction further so that's the answer.

3 0
2 years ago
What is the sign of f on the interval -7/3
Greeley [361]

Answer:

C is the answers for the question

7 0
3 years ago
Andrew went for a walk in the park. The trail he took is 1 1/4 miles long. He walked for 1/2 mile before stopping for a water br
garik1379 [7]

Andrew walked for 3/4 miles after his break

<h3>How to calculate the number of miles Andrew walked after the break ? </h3>

Andrew went for a walk

The trail he took is 1 1/4 miles long

He walked for 1/2 miles before stopping for a water break

After the break, he continued the journey

He continued the journey without stopping

The distance Andrew walked after his break can be calculated as follows

5/4 - 1/2

= 5-2/4

= 3/4

Hence Andrew walked for 3/4 miles after taking the break

Read more on miles here

brainly.com/question/14085856

#SPJ1

6 0
1 year ago
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