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harina [27]
4 years ago
14

Determine the number of acute, obtuse, and right angles in the shape above.

Mathematics
1 answer:
stich3 [128]4 years ago
4 0

Answer:

Step-by-step explanation:

You should never be given a question that has a diagram that looks  like it could be so.

That being said there is

1 obtuse angle (lower left)

1 right angle (top right)

2 acute angles (the two angles that are left).

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1. 42<br><br> 2.70<br><br> 3.35<br><br> 4.84<br><br> Helpppppppppp
vitfil [10]
Answer = 84

Step-by-step explanation :

Area = b • h

14 = b
6 = h

14 • 6 = 84
4 0
3 years ago
Read 2 more answers
Find the product (a*2-4b)(2a*2+b)
Karo-lina-s [1.5K]

(a*2-4b)(2a*2+b) Regroup terms.

(2a−4b)(2×2a+b) Simplify 2*2a=4a

the answer is (2a−4b)(4a+b)

Hope this helps, now you know the answer and how to do it. HAVE A BLESSED AND WONDERFUL DAY! As well as a great rest of Black History Month! :-)  

- Cutiepatutie ☺❀❤

8 0
3 years ago
X + y = 12
liberstina [14]
We are given with two equations to find the values of two variables, hence the problem can be solved.

Adding the two equations:

x + y = 12<u>x - y = 10
</u>2x    = 22
<u />x =11
y = 1
8 0
4 years ago
Read 2 more answers
Ms cohn divide 21 markers equally among 7 .Write an equation to show how many markers each student gets.then write a related fac
stira [4]

Answer:

Hello There!!

Step-by-step explanation:

21/7=3

21 are the total markers and you divide by 7 so 7 goes 3 times into 21.

hope this helps,have a great day!!

~Pinky~

6 0
3 years ago
State how many imaginary and real zeros the function has.
alukav5142 [94]

Answer:

B. 4 imaginary; 1 real

Step-by-step explanation:

Given the polynomial:

x^5 + 7*x^4 + 2*x^3 + 14*x^2 + x + 7

it can be reordered as follows

(x^5 + 2*x^3 + x ) + (7*x^4  + 14*x^2 + 7)

Taking greatest common factor at each parenthesis

x*(x^4 + 2*x^2 + 1) + 7*(x^4  + 2*x^2 + 1)

Taking again the greatest common factor

(x + 7)*(x^4 + 2*x^2 + 1)

Replacing x^2 = y in the second parenthesis

(x + 7)*(y^2 + 2*y + 1)

(x + 7)*(y + 1)^2

Coming back to x variable

(x + 7)*(x^2 + 1)^2

There are two options to find the roots

(x + 7) = 0

or

(x^2 + 1)^2 = 0 which is the same that (x^2 + 1) = 0

In the former case, x = -7 is the real root.  In the latter, (x^2 + 1) = 0 has no real solution. Therefore, there is only 1 real root in the polynomial.

8 0
3 years ago
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