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Taya2010 [7]
3 years ago
15

X + y = 12

Mathematics
2 answers:
liberstina [14]3 years ago
8 0
We are given with two equations to find the values of two variables, hence the problem can be solved.

Adding the two equations:

x + y = 12<u>x - y = 10
</u>2x    = 22
<u />x =11
y = 1
Agata [3.3K]3 years ago
3 0

Answer:

Option C is correct

value of the x-determinant for the system is, -2

Step-by-step explanation:

Given the system of equation:

x + y =12

x -y =10

Represents the system of equations in matrix format:

\begin{bmatrix} 1 & 1\\ 1 & -1 \end{bmatrix}\begin{bmatrix}x\\y\end{bmatrix} = \begin{bmatrix}12\\ 10\end{bmatrix}

Now, to find the determinant of a matrix.

Formula for the determinant of matrix:

\begin{bmatrix}a & b\\ c & d\end{bmatrix} = ad-bc

then;

The value of the x-determinant:

\begin{bmatrix}1 & 1\\ 1 & -1\end{bmatrix}

Using determinant(D) formula:

D= (1)(-1)-(1)(1) = -1 -1 = -2

Therefore, the value of the x-determinant for the system is, -2


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Plz help me out with this
nadya68 [22]

Given,

  • HK is the perpendicular bisector of GJ. So, <u>GK = KJ</u>.
  • GK = 2x + 10
  • KJ = 3x - 15

_______________

Find KJ .

_______________

First find the value of x

\sf \: GK \:  = KJ \\\sf 2x + 10 = 3x - 15 \\\sf 2x - 3x =  - 15 - 10 \\ \sf - x =  - 25 \\  \sf \: -  >   \boxed{\bf \: x = 25}

Now, find the value of KJ.

\sf3x - 15 \\  \sf= 3(25) - 15 \\  \sf=7 5 - 15 \\     = \boxed{\bf \: 60}

-> The value of KJ is <u>6</u><u>0</u><u>.</u>

_______________

Hope it helps.

RainbowSalt2222

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Tim's credit card has a restriction that he must pay either 15 percent of the unpaid balance or $25, whichever is greater
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He has to pay 15% as that is 32 and more than $25

Step-by-step explanation:

If you take 15% out of 216 it will become 32.

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If the area of a square is 100 cm2, what is the perimeter?<br>​
Vitek1552 [10]

Answer:

40

Step-by-step explanation:

To find the perimeter, first we need to find the side lengths.

If 100 cm is the area then we need to find what number squared is 100

10 x 10 = 100

So 10 is the side length. P= s + s + s +s

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6 0
2 years ago
A. Use composition to prove whether or not the functions are inverses of each other. B. Express the domain of the compositions u
Kryger [21]

Given: f(x) = \frac{1}{x-2}

           g(x) = \frac{2x+1}{x}

A.)Consider

f(g(x))= f(\frac{2x+1}{x} )

f(\frac{2x+1}{x} )=\frac{1}{(\frac{2x+1}{x})-2}

f(\frac{2x+1}{x} )=\frac{1}{\frac{2x+1-2x}{x}}

f(\frac{2x+1}{x} )=\frac{x}{1}

f(\frac{2x+1}{x} )=1

Also,

g(f(x))= g(\frac{1}{x-2} )

g(\frac{1}{x-2} )= \frac{2(\frac{1}{x-2}) +1 }{\frac{1}{x-2}}

g(\frac{1}{x-2} )= \frac{\frac{2+x-2}{x-2} }{\frac{1}{x-2}}

g(\frac{1}{x-2} )= \frac{x }{1}

g(\frac{1}{x-2} )= x


Since, f(g(x))=g(f(x))=x

Therefore, both functions are inverses of each other.


B.

For the Composition function f(g(x)) = f(\frac{2x+1}{x} )=x

Since, the function f(g(x)) is not defined for x=0.

Therefore, the domain is (-\infty,0)\cup(0,\infty)


For the Composition function g(f(x)) =g(\frac{1}{x-2} )=x

Since, the function g(f(x)) is not defined for x=2.

Therefore, the domain is (-\infty,2)\cup(2,\infty)



8 0
3 years ago
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