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Anon25 [30]
3 years ago
7

If (42)^p = 41^4, what is the value of p?

Mathematics
1 answer:
babymother [125]3 years ago
4 0

First you need to make both bases the same:

Lets remove the ^p and ^4

To make the base of 42 equal to 41, you would have 41^x = 41

X - ln(42) / ln(41) = 1.00648904


Now you have 41^1.00648904(p) = 41^4


Now the bases are equal so we need to set the exponents to equal:

1.00648904(p) = 4

Divide both sides by 1.00648904 to solve for P

P = 4 / 1.00648904

P = 3.97421114

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the answer is <em><u>X</u></em><em><u>=</u></em><em><u>-</u></em><em><u>3</u></em>

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<u>2</u><u>)</u><u>5</u><em><u>x</u></em><u>^</u><u>2</u><u>+</u><u>1</u><u>7</u><em><u>x</u></em><em><u>=</u></em><em><u>-</u></em><em><u>1</u></em><em><u>4</u></em><em><u>+</u></em><em><u>0</u></em>

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<em><u>4</u></em><em><u>)</u></em><em><u>4</u></em><em><u>2</u></em><em><u>x</u></em><em><u>=</u></em><em><u>-</u></em><em><u>1</u></em><em><u>4</u></em>

<em><u>5</u></em><em><u>)</u></em><em><u>4</u></em><em><u>2</u></em><em><u>x</u></em><em><u>/</u></em><em><u>-</u></em><em><u>1</u></em><em><u>4</u></em>

<em><u>6</u></em><em><u>)</u></em><em><u>x</u></em><em><u>=</u></em><em><u>-</u></em><em><u>3</u></em>

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