If (42)^p = 41^4, what is the value of p?

Mathematics

1 answer:

babymother [125]4 years ago

4 0

First you need to make both bases the same:

Lets remove the ^p and ^4

To make the base of 42 equal to 41, you would have 41^x = 41

X - ln(42) / ln(41) = 1.00648904

Now you have 41^1.00648904(p) = 41^4

Now the bases are equal so we need to set the exponents to equal:

1.00648904(p) = 4

Divide both sides by 1.00648904 to solve for P

P = 4 / 1.00648904

P = 3.97421114

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Answer:

128 ft sq.

Step-by-step explanation:

The way you find the area of a square is by multiplying one side by another, and since it is a square, the sides are the same. This means that if we have a square with a side length of x, the way to find the area of that square is to multiply x by x, which can be written as $x^2$ . Now, since we're doubling this, we can say that double Mary's garden is $2 * x^2$ . If we substitute 8 in for x, we have to multiply $8^2$ by 2 or 8 by 8 by 2 to find our answer. 8 times 8 is 64 and 64 times 2 is 128.