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Sophie [7]
3 years ago
11

A recursive rule for a geometric sequence is a1=2; an= 4/9 an-1

Mathematics
1 answer:
Oxana [17]3 years ago
3 0

A recursive rule for a geometric sequence:

a_1\\\\a_n=r\cdot a_{n-1}

---------------------------------------------------

a_1=2;\ a_n=\dfrac{4}{9}a_{n-1}\to r=\dfrac{4}{9}

---------------------------------------------------

The exciplit rule:

a_n=a_1r^{n-1}

Substitute:

a_n=2\left(\dfrac{4}{9}\right)^{n-1}=2\cdot\left(\dfrac{4}{9}\right)^n\cdot\left(\dfrac{4}{9}\right)^{-1}=2\cdot\left(\dfrac{4}{9}\right)^n\cdot\dfrac{9}{4}\\\\\boxed{a_n=\dfrac{9}{2}\cdot\left(\dfrac{4}{9}\right)^n}

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For the perimeters to be the same

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Part B:

The area of the square is given by

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The area of the rectangle is given by 2(3x + 4) = 6x + 8

For the areas to be the same

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