The numbers are: 36 and 11 .
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Explanation:
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Let us represent the TWO (2) numbers with the variables;
"x" and "y" .
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x + y = 47 .
y − x = 25.
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Since: " y − x = 25 " ;
Solve for "y" in terms of "x" ;
y − x = 25 ;
Add "x" to each side of the equation:
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y − x + x = 25 + x ;
to get:
y = 25 + x .
Now, since:
x + y = 47 ;
Plug in "(25 + x)" as a substitution for "y"; to solve for "x" :
x + (25 + x) = 47 ;
x + 25 + x + 47 ;
2x + 25 = 47 ;
Subtract "25" from each side of the equation:
2x + 25 − 25 = 47 − 25 ;
2x = 22 ;
Divide EACH SIDE of the equation by "2" ;
to isolate "x" on one side of the equation; and to solve for "x" ;
2x / 2 = 22 / 2 ;
x = 11 ;
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x + y = 47<span> ;
</span>Plug in "11" for "x" into the equation ; to solve for "y" ;
11 + y = 47 ;
Subtract "11" from EACH SIDE of the equation;
to isolate "y" on one side of the equation; and to solve for "y" ;
11 + y − 11 = 47 − 11 ;
y = 36 .
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So: x = 11 , y = 36 ;
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Let us check our work:
y − x = 25 ;
36 − 11 =? 25 ? Yes!
x + y = 47 ;
36 + 11 =? 47 ? Yes!
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The numbers are: 36 and 11 .
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Answer:
35 like rap 25 dont like rap
Step-by-step explanation:
Ok so linear equations come in the form
y = mx + b
B is the y-intercept. In this equation the y intercept is 40. A y- intercept is where the graph crosses the y axis so at the point (0,40) the graph crosses the y axis.
M is the slope which is rise over run so if the slope was 10 (which it is) 10 is equivalent to 10/1 so you move up 10 units for every 1 unit you move across.
So to graph this equation, you would draw your first point at (0,40). For your next point, you would move right one unit, and up 10 units. Draw a point there which would be (1, 50). Hopefully you understand. For going left from the y intercept point, you would move left 1 and down 10.
Actual graph above.
Hope this helps C:
Answer:
198 cubic metres
Steps:
<em><u>Find </u></em><em><u>the </u></em><em><u>area </u></em><em><u>of </u></em><em><u> </u></em><em><u>cross</u></em><em><u> </u></em><em><u>section</u></em>
<em><u>Area </u></em><em><u>if </u></em><em><u>traing</u></em><em><u>l</u></em><em><u>e </u></em><em><u>+</u></em><em><u> </u></em><em><u>Area </u></em><em><u>of </u></em><em><u>square</u></em>
<em><u>1</u></em><em><u>/</u></em><em><u>2</u></em><em><u> </u></em><em><u>×</u></em><em><u> </u></em><em><u>3</u></em><em><u> </u></em><em><u>×</u></em><em><u> </u></em><em><u>4</u></em><em><u> </u></em><em><u>+</u></em><em><u> </u></em><em><u>4</u></em><em><u>×</u></em><em><u>4</u></em>
<em><u>6</u></em><em><u>+</u></em><em><u> </u></em><em><u>1</u></em><em><u>6</u></em>
<em><u>2</u></em><em><u>2</u></em>
<em><u>Then </u></em><em><u>times </u></em><em><u>with </u></em><em><u>the </u></em><em><u>lenght </u></em><em><u>(</u></em><em><u>9</u></em><em><u>)</u></em>
<em><u>2</u></em><em><u>2</u></em><em><u>×</u></em><em><u>9</u></em>
I hope this helps, dont hesitate to ask for any question.
Mark me as brainliest is appreciated.Tq!!
So basically you need to ......
Hope it helps