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2 years ago

What is the product? 7•(-3)

Mathematics

1 answer:

ANTONII [103]2 years ago

8 0

-21 is the product!!!!!!

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Find the unknown 8/28 = m/7

vredina [299]

The answer to the question is m = 2

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3 years ago

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Find the vertex and the axis of symmetry of the graph of the function?

Orlov [11]

3) Vertex: (-7, 0) Axis of Symmetry: x=-7
6) Vertex: (-2, -1) Axis of Symmetry: x=-2

5 0

3 years ago

Given f (X) = 4x +6 find f (x) = 54

Nikitich [7]

Answer:

x = 12

Step-by-step explanation:

Step 1: Define

f(x) = 4x + 6

f(x) = 54

Step 2: Substitute variables

54 = 4x + 6

Step 3: Solve for <em>x</em>

<u>Subtract 6 on both sides:</u> 48 = 4x

<u>Divide both sides by 4:</u> 12 = x

Step 4: Check

<em>Plug in x to verify it is a solution.</em>

f(12) = 4(12) + 6

f(12) = 48 + 6

f(12) = 54

3 0

3 years ago

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Jack spent 1/3 hour cleaning his room which fraction is equivalent

Vinil7 [7]

Answer:

2/6

Step-by-step explanation:

1/3

Write an equivalent fraction by multiplying

1/3 * 2/2

2/6

I hope this was useful!

4 0

3 years ago

write the logarithm as a sum or difference of logarithms. simplify each term as much as possible. log4(6ab)

Dominik [7]

The logarithm written as a sum of logarithm and simplified as much as possible is $\frac{1}{2} +log_{4 }3 + log_{4 }a + log_{4 }b$

<h3>Simplifying Logarithms</h3>

From the question, we are to write the given logarithm expression as a sum or difference of logarithms

The given logarithm is

$log_{4 }6ab$

This can be written as

$log_{4 }6 \times a \times b$

From one of the rules of logarithm, we have that

$log_{x }yz= log_{x }y + log_{x }z$

Thus,

$log_{4 }6 \times a \times b$ becomes

$log_{4 }6 + log_{4 }a + log_{4 }b$

This can be further simplified into

$log_{4 }3 \times 2 + log_{4 }a + log_{4 }b$

$log_{4 }3 + log_{4 }2 + log_{4 }a + log_{4 }b$

If desired, this can be further simplified into

$log_{4 }3 + log_{2^{2} }2 + log_{4 }a + log_{4 }b$

$log_{4 }3 + \frac{1}{2} log_{2}2 + log_{4 }a + log_{4 }b$

$log_{4 }3 + \frac{1}{2} (1)+ log_{4 }a + log_{4 }b$

$\frac{1}{2} +log_{4 }3 + log_{4 }a + log_{4 }b$

Hence, the logarithm written as a sum of logarithm and simplified as much as possible is $\frac{1}{2} +log_{4 }3 + log_{4 }a + log_{4 }b$

Learn more on Simplifying logarithms here: brainly.com/question/17851187

#SPJ1

8 0

1 year ago