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zhannawk [14.2K]
3 years ago
6

Write the domain and range as an inequality.

Mathematics
1 answer:
BaLLatris [955]3 years ago
4 0

Answer:

Step-by-step explanation:

domain is (-3,x) x- inter

range is (x,2) y-inter

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Help ASAP! Voting all answers as 5 stars with a thanks. (:
FinnZ [79.3K]

Answer:

A=68

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Hello everyone can you answer this for me? What is A in the equation attached? Please and thank you.
lapo4ka [179]

Answer:

a = 6

Step-by-step explanation:

Hello!

Solve:

  • 4(3a - 4) = 56
  • 3a - 4 = 14          (factoring out 4)
  • 3a = 18               (adding 4 to both sides)
  • a = 6                   (dividing by 3)

Another way:

  • 4(3a - 4) = 56
  • 12a - 16 = 56        (distributive property)
  • 12a = 72               (moving like terms)
  • a = 6                    (dividing by 12)

Distributive Property of Multiplication:

The process of distributing the outside factor to the terms in the parenthesis.

Example:

4(3a - 4)\\\\4(3a) - 4(4)\\\\12a - 16

7 0
3 years ago
Read 2 more answers
What 7482 + y + A -2937?
s344n2d4d5 [400]

Answer:

4545+y+A

Step-by-step explanation:

It cant be solved it can only be simplified down to 4545+y+A

3 0
3 years ago
Plz help I have no idea how to answer it​
saveliy_v [14]

5. Answer: see explanation

<u>Step-by-step explanation:</u>

If the roots are m and 3m, then x = m and x = 3m

⇒ x - m = 0    and      x - 3m = 0

⇒ (x - m)(x - 3m) = 0

⇒ x² - 4mx + 3m² = 0

Since x² + px + q = 0   then  p = -4m   and q = 3m²

3p² = 3(-4m)²               16q = 16(3m²)

      = 3(16m²)                      = 48m²

      = 48m²

3p² = 48m² = 16q     ⇒           3p² = 16q

**********************************************************************************************

6. Answer: 8 or 18

<u>Step-by-step explanation:</u>

The Area of the entire rectangle (A = L × w) is 12 × 10 = 120

The Area of the shaded region is 72, so the Area of the non-shaded region is 120 - 72 = 48.

There are two non-shaded triangles.

  • Bigger non-shaded Δ: L = 12-x, w = 10  ⇒ A = \dfrac{10(12-x)}{2}
  • Smaller non-shaded Δ: L = x, w = x ⇒ A=\dfrac{x(x)}{2}

Combine the Areas of both triangles and set it equal to the Area of the non-shaded region:

\dfrac{x(x)}{2}+\dfrac{10(12-x)}{2}=48\\\\\\\dfrac{x^2}{2}+\dfrac{120-10x}{2}=48\\\\\\\dfrac{x^2-10x+120}{2}=48\\\\\\x^2-10x+120=96\\\\x^2-10x+24=0\\\\(x-4)(x-6)=0\\\\x - 4 = 0\quad or\quad x-6=0\\x=4\qquad or\qquad x=6\\\\\text{Based on the image provided, it appears that the x-value will be the}\\\text{smallest of the two possible solutions (4), but both solutions are valid.}

Area of ΔBEF:

\text{when x = 4, A =}\ \dfrac{4(4)}{2}=\dfrac{16}{2}=8\\\\\\\text{when x = 6, A =}\ \dfrac{6(6)}{2}=\dfrac{36}{2}=18

5 0
3 years ago
The HCF and LCM of two numbers is 9 and 459 respectively if one the number is 27 the other number is (1)
dezoksy [38]

Answer:

153

Step-by-step explanation:

other \: number =  \frac{9 \times 459}{27}  \\  \\  =  \frac{459}{3}  \\  \\  = 153

5 0
3 years ago
Read 2 more answers
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