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sergeinik [125]
3 years ago
11

I) If a, b, care in continued proportion then show that,(a+b)2/ab=(b+c)2/bc​

Mathematics
1 answer:
natali 33 [55]3 years ago
5 0
Here is your perfect answer

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What is the answer now in two minutes
Wittaler [7]

Answer:

60 degrees

Step-by-step explanation:

Cos of 60 is 1/2, unit circles helps with this.

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3 years ago
Drey makes $10 an hour plus $15 an hour for every hour of overtime. Overtime hours are any hours more than 40 hours for the week
alekssr [168]

Drey makes $10 an hour plus $15 an hour for every hour of overtime. Overtime hours are any hours more than 40 hours for the week.

Part A: Create an equation that shows the amount of wages earned, W, for working x hours in a week when there is no overtime. 

If there is no overtime, the equation is W = 10x.

Part B: Create an equation that shows the amount of wages earned, S, for working y hours of overtime. Hint: Remember to include in the equation the amount earned from working 40 hours. 

At $10 per hour for 40 hours, the total is $400.

S = 15y + 400

Part C: Drey earned $490 in 1 week. How many hours (regular plus overtime) did he work?

490 = 15y + 400

490 - 400 = 15y

90 = 15y

90/15 = y

6 = y

Drey worked 46 hours in all.




4 0
2 years ago
What is the greatest common factor of 14 and 35
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14|2\\.\ 7|7\\.\ 1|\\\\14=2\times\boxed7\\\\35|5\\.\ 7|7\\.\ 1|\\\\35=5\times\fbox7\\\\LCD(14;\ 35)=\boxed7
8 0
3 years ago
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Write 2 quadratic equations that are NOT equivalent, each forming a graph with X-
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Help me I’ll mark you brainly!xikakdkdkdjjsjdjdieixiwiisisixkixzkksisisisxxiixidisisoosososososososziiss Help me I’ll mark you brainly! Help me I’ll mark you brainly!
5 0
3 years ago
Jaylon Bedford ordered a combo meal that included 2 hamburgers and a drink. The combo cost $8.50. If the drink is $1.50, how muc
valentinak56 [21]

Answer:

$3.50 each

Step-by-step explanation:

First subtract the drink price from the total,$8.50-$1.50=$7. then divide that amount by 2 since he got 2 burgers. $7/2=$3.50.Each burger is $3.50.

7 0
3 years ago
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