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Natasha_Volkova [10]
3 years ago
12

Can somebody help me please? I haven’t gotten help at all.

Mathematics
1 answer:
Elena-2011 [213]3 years ago
4 0

Answer:

f(x) = -3x+12

I would advise you to study this part again :)

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Using technology, determine the quarterly payment on a 4 year loan of $16,231 at 5.1% compounded quarterly. round your answer to
Vesna [10]

The quarterly payment will be $1,127.86

<h3>What is compound interest?</h3>

Compound interest is the interest on a loan or deposit that  levied on both the first principal and the collected interest from past periods.

The amortization formula is ...

A=\dfrac{P\timesr}{(1-(1+r)^{-n}}

where A is the payment amount, P is the principal amount, r is the interest rate per period, and n is the number of periods.

Here, we have

P=$16,231, r=0.051/4=0.01275, n=4·4=16.

So, the payment is ...

A=\dfrac{16231\times 0.01275}{1-(1.01275)^{-16}}  

A=$1127.86

Hence the quarterly payment amount is $1,127.86.

To know more about Compound interest, follow

brainly.com/question/24924853

8 0
2 years ago
What is the expanded form of this number?
Jlenok [28]

Answer:

Number 2

Step-by-step explanation:

Number two. Okay?

5 0
3 years ago
Find the area of the window<br><br><br>​
nirvana33 [79]

Answer:

Area = 1250cm²

Step-by-step explanation:

Area of a kite = pq/2

where p and q are diagonals

p = 25+25 = 50

q = 30+ 20 = 50

Area of a kite = pq/2

Area = (50*50 ) / 2

Area = 1250cm²

3 0
2 years ago
Laura can drive her car 260 miles on 10 gallons of gasoline. Michael can drive his car 280 miles on
Marianna [84]
Michael

Michel Can travel 70 mile on one gallon which is 1400 miles on 20 gallons

Laura can only travel 26 miles on one gallon which is 520 miles on 20 gallons
4 0
3 years ago
Let f be a continuous function defined on the interval [0,1] such that f(0) = f(1). Show that there exists a number 0 &lt;= a &l
Leni [432]

Explanation:

In order to prove that affirmation, we define the function g over the interval [0, 1/2] with the formula g(x) = f(x+1/2)-f(x) .

If we evaluate g at the  endpoints we have

g(0) = f(1/2)-f(0) = f(1/2) - f(1) (because f(0) = f(1))  

g(1/2) = f(1) - f(1/2) = -g(0)

Since g(1/2) = -g(0), we have one chance out of three

  • g(0) > 0 and g(1/2) < 0
  • g(0) < 0 and g(1/2) > 0
  • g(0) = g(1/2) = 0

We will prove that g has a zero on [0,1/2]. If g(0) = 0, then it is trivial. If g(0) ≠ 0, then we are in one of the first two cases, and therefore g(0) * g(1/2) < 0. Since f is continuous, so is g. Bolzano's Theorem assures that there exists c in (0,1/2) such that g(c) = 0.  This proves that g has at least one zero on [0,1/2].

Let c be a 0 of g, then we have

0 = g(c) = f(c+1/2)-f(c)

Hence, f(c+1/2) = f(c) as we wanted.

5 0
3 years ago
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