Ask question

Ask question

All categories

2 years ago

14

-9/4 v + 4/5 = 7/8 v=? step by step need help asap please

1 answer:

Vesna [10]2 years ago

4 0

-9/4v + 4/5 = 7/8; First, you subtract 4/5 from each side to have variable v on a side and numbers on the other: -9/4v = 7/8 - 4/5; -9/4v = 35/40 - 32/40; -9/4v = 3/40; Then you divide each side to get the variable v alone on a side, and one number on the other: V= (3/40) / (-9/4); Dividing to fractions is equal to multiplying the first one by the inverse of the second: V= (3/40) * (-4/9); V= -12/360; V= -1/30; You can re-check your answer (very important): (-9/4)*(-1/30)+4/5=7/8; The answer has been approved. Hope this helps! :)

You might be interested in

Write a word problem that can be solved by ordering three decimals to thousandths include a solution

Mariana [72]

<span>If I have a bolt that has a diameter of 1.125 inches and a hole that's 1.300 inches with a tolerance of +/- 0.025 inches, what's the larger even tolerance I can have on the bolt to ensure it will pass through the hole? Answer: +/- 0.150 inches.</span>

8 0

3 years ago

Use the function shown in the table to answer the questions below .

Lubov Fominskaja [6]

Answer:

a) -6

b) 3

c) Y = -6x + 3

Step-by-step explanation:

Pick two points and find rise/run = slope

rise y1 - y2 = 9 - 3 = 6

run x1 - x2 = -1 - 0 = -1

slope = 6 / -1 = -6

The y intercept is where x = 0 which is given in the table (0,3) so

y intercept = 3

Point slope form is y = mx + b , so

y = -6x + 3

7 0

2 years ago

How can 563*10 to the 3rd power be scientific notation.(Use the photo above please)

zaharov [31]

563*(10*10*10) that's you scientific notation

6 0

3 years ago

Which of the following values could the number 500,000 be composed of?

OverLord2011 [107]

50000 tens

5000hundreds

How?

1ten=10

50000 tens:-

$\\ \sf\longmapsto 50000(10)=500000$

1hundred=100

5000hundreds

$\\ \sf\longmapsto 5000(100)=500000$

8 0

2 years ago

Read 2 more answers

Let Ebe the set of all even positive integers in the universe Zof integers, and XE : Z R be the characteristic function of E.

AnnZ [28]

Answer:

$\mathbf{X_E (2) = 1}$

$\mathbf{X_E (-2) = 0 }$

$\mathbf{\{ x \in Z: X_E(x) = 1\} = E}$

Step-by-step explanation:

Let E be the set of all even positive integers in the universe Z of integers,

i.e

E = {2,4,6,8,10 ....∞}

$X_E : Z \to R$ be the characteristic function of E.

∴

$X_E(x) = \left \{ {{1 \ if \ x \ \ is \ an \ element \ of \ E} \atop {0 \ if \ x \ \ is \ not \ an \ element \ of \ E}} \right.$

For XE(2)

$\mathbf{X_E (2) = 1}$ since x is an element of E (i.e the set of all even numbers)

For XE(-2)

$\mathbf{X_E (-2) = 0 }$ since - 2 is less than 0 , and -2 is not an element of E

For { x ∈ Z: XE(x) = 1}

This can be read as:

x which is and element of Z such that X is also an element of x which is equal to 1.

∴

$\{ x \in Z: X_E(x) = 1\} = \{ x \in Z | x \in E\} \\ \\ \mathbf{\{ x \in Z: X_E(x) = 1\} = E}$

E = {2,4,6,8,10 ....∞}

5 0

2 years ago