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VLD [36.1K]
3 years ago
15

He mean potassium content of a popular sports drink is listed as 140 mg in a 32-oz bottle. Analysis of 20 bottles indicates a sa

mple mean of 139.4 mg. (a) State the hypotheses for a two-tailed test of the claimed potassium content.
(A) H0: μ = 140 mg vs. H1: μ ≠ 140 mg
(B) H0: μ ≤ 140 mg vs. H1: μ > 140 mg
(C) H0: μ ≥ 140 mg vs. H1: μ < 140 mg
Mathematics
1 answer:
mezya [45]3 years ago
3 0

Answer: (A) H0: μ = 140 mg vs. H1: μ ≠ 140 mg

Step-by-step explanation:

Usually null hypothesis represents the claim that the values associated to the groups being tested have no statistical difference but alternative hypothesis supports the claim that there is statistical difference.

Let \mu be the population mean .

We are given that the mean potassium content of a popular sports drink is listed as 140 mg in a 32-oz bottle.

i.e. Null hypothesis :H_0:\mu=140

Alternative hypothesis for two tail hypothesis has sign (≠).

i.e. Alternative hypothesis : H_1 : \mu\neq140

∴ The hypotheses for a two-tailed test of the claimed potassium content:

H0: μ = 140 mg vs. H1: μ ≠ 140 mg

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<h3><u>Solution:</u></h3>

Given that yoko borrows $3500.

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Need to determine amount owed at the end of 1 year.

In our case :

Borrowed Amount that is principal P = $3500

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Duration = 1 year and as it is compounded yearly, number of times interest calculated in 1 year n = 1

<em><u>Formula for Amount of compounded yearly is as follows:</u></em>

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