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Viktor [21]
4 years ago
13

Which repeating decimal is equal in value to the fraction below? 8/9

Mathematics
2 answers:
Goshia [24]4 years ago
4 0
1/9 = 0.11111...
8/9 = 0.888888...
amm18124 years ago
3 0
Can be achieved by dividing.
                ___
8 ÷ 9 = 0.8888

Therefore the answer is B
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(1-w-w²)⁶=64 prove thta​
VLD [36.1K]

1−w−w2=64

Step 1: Simplify both sides of the equation.

−w2−w+1=64

Step 2: Subtract 64 from both sides.

−w2−w+1−64=64−64

−w2−w−63=0

For this equation: a=-1, b=-1, c=-63

−1w2+−1w+−63=0

Step 3: Use quadratic formula with a=-1, b=-1, c=-63.

w= −b±√b2−4ac /2a

w= −(−1)±√(−1)2−4(−1)(−63) /2(−1)

w= 1±√−251/ −2

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7x + 3 = -41 what’s the answer
nika2105 [10]

Answer: x = -44/7

Step-by-step explanation:

Step 1: Subtract 3 from both sides.

7x+3−3=−41−3

7x=−44

Step 2: Divide both sides by 7.

7x/7 = -44/7

Answer:

-44/7

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5.241 divided by 3 please help me​
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A model rocket is launched from the top of a building. The height(in meters) of the rocket above the ground is given by h(t)=-6t
Shalnov [3]

Answer:

Step-by-step explanation:

I don't know if you are a calculus student, but since calculus is the easiest way to solve this, that's what I used.  The position equation is

s(t)=-6t^2+24t+14

and the velocity function, the first derivative, is

v(t)=-12t+24

From Physics, you should know that the velocity of an object is 0 at its highest point.  That means that if we sub in a 0 for the velocity and solve for t, we find the time at which the object is at its highest point.  That is:

0=-12t+24 and

0=-12(t-2)

By the Zero Product Property,

-12 definitely does not equal 0, so that means that

t - 2 = 0 and

t = 2 seconds.

So at 2 seconds, the object is at its highest point.  Go back to the position function now and sub in a 2 for t to find the height of the object at 2 seconds.

s(2)=-6(2)^2+24(2)+14 so

s(2) = 38 meters

7 0
3 years ago
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