We would need to look over the z table to find the area under the standard normal distribution curve to the left of z = 1.04. Then we'll subtract it from 1 to get the proportion of a normal distribution corresponding to z scores greater than 1.04.
By looking at the z table, we can see that the area to the left of z = 1.04 is 0.8508. So the proportion of a normal distribution to the right of z = 1.04 is 1 – 0.8508 = 0.1492.
The answer is 0.1492.
There would be 2034 students competing in 2012.
We can write a simple equation to find this answer. Let X, be the number of students starting in 2012. Then, we multiply by 0.9 and 1.1 to get to 2014. To work backwards, just divide by 1.1, then by 0.9.
2014 / 1.1 / 0.9 = 2034
Answer:
Probability that first sock is blue is 0.33 and Probability that second sock is red is 0.16
Step-by-step explanation:
Number of red socks = 2
Number of white socks = 6
Number of blue socks = 4
Total socks in drawer = 2+6+4 = 12
The formula used to calculate probability is: 
We are given you draw out a sock, return it, and draw out a second sock.
We need to find the probability that the first sock is blue and the second sock is red?
Using formula:
Probability that first sock is blue = 4/12 = 1/3 = 0.33
Probability that second sock is red = 2/12 = 1/6 = 0.16
So, Probability that first sock is blue is 0.33 and Probability that second sock is red is 0.16
Assuming what is meant by "infinite solutions" are infinite number of solutions of a logarithmic equation.

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