In pea plants, the gene for the color of the seed has two alleles. In the following Punnett square shown below, the dominant all
ele (Y) represents yellow and the recessive allele (y) represents green. Punnett Square showing a grid that is blank with 4 empty boxes, two columns and two rows. The female parent plant across the horizontal side, top, of the grid indicates a yellow phenotype and a genotype of Yy. The male parent plant along the vertical side of the grid indicates a yellow phenotype and a genotype of YY. Based on the Punnett square, what percentage of offspring would be expected to have yellow seeds? 0% 25% 50% 100% Question 6(Multiple Choice Worth 3 points) (06.03 LC) A Punnett square is used to _______. predict the genotypic and phenotypic probabilities of possible offspring determine if a trait runs in a family track inherited traits through many generations identify organisms that are carriers of a specific trait Question 7(Multiple Choice Worth 3 points) (06.03 MC) A tall pea plant (Tt) is crossbred with another tall pea plant (Tt). The following Punnett square shows the separated alleles for two pea plants. Punnett square showing female parent across the top with a phenotype of tall and a genotype of Tt and a male parent across the side with a phenotype of tall and a genotype of Tt. Inside the top left box 1 is written, inside the top right box 2 is written, inside the bottom left box 3 is written, inside the bottom right box 4 is written. Which of the following shows the correct match of the box numbers and the genotype of the offspring? 1 = Tt; 2 = tt; 3 = Tt; 4 = tt 1 = Tt; 2 = Tt; 3 = Tt; 4 = Tt 1 = TT; 2 = Tt; 3 = Tt; 4 = tt 1 = TT; 2 = TT; 3 = Tt; 4 = t
1 answer:
<h2>Question 1.</h2><h2>Answer:</h2>
The correct answer is option D which is 100%.
<h3>Explanation:</h3>According to the description of Punnett square given in the question, there will be there will be two types of genotype and one type of phenotype which is yellow.
- YY, homozygous dominant = Yellow Seeds.
- Yy, heterozygous = Yellow Seeds
- So the progeny will be 100% of yellow seeds.
Punnett square is also attached.
<h2>Question No.2.</h2><h2>Answer:</h2>The correct answer is the option A which predicts the genotypic and phenotypic probabilities of possible.
<h3>Explanation:</h3><u><em>Punnett square is a way to determine the probable genotype of expected offspring by the genotypes of father and mother devised by Punnett.</em></u>
- In this method, A square shaped table is constructed and the alleles of the gene of father/male are written on the top of tables, on the column.
- The alleles of the mother are written in horizontal to square, in front of rows.
- So the genotypes in the square box by multiplying row and column alleles will be expected genotype of an offspring.
- The example is attached below.
The correct answer is option C which is 1 = TT; 2 = Tt; 3 = Tt; 4 = tt .
<h3>Explanation:</h3>The Punnett square is made by the description given in the question.
There are total 4 boxes. In box number 1 which is on top left genotype is TT and in box 2 which is on top right genotype is Tt. In box 3, the genotype is Tt and in box 4, the genotype is tt.
So according to the given Punnett square information in option C is correct one.
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Answer:
Waldemar carried the recessive allele.
Explanation:
The carrier is the individual that has the affected allele or mutation but does not express the trait, or might express it in different levels. Although, as the person carries the mutation, she or he might transmit the genetic mutation associated with a disease to the progeny. In general, these diseases are inherited as recessive traits.
So, in the exposed example we know that:
- hemophilia is a sex-linked disorder
- hemophilia is determined by a recessive allele on the X chromosome.
- Irene is a carrier.
- Her husband is not a carrier.
- Her children Waldemar and Henry have hemophilia.
If Irene is a carrier, this means that she is heterozygous and that her genotype is X⁺X⁻ (Being the symbol + the dominant allele, and - the recessive one for that expresses the trait)
The fact that Irene´s husband is not a carrier means that his genotype is X⁺Y
Their boys Waldemar and Henry have hemophilia, so both their genotypes are X⁻Y
The best evidence to prove that Irene was heterozygous for hemophilia is that Alice carried the recessive allele.
- Alice is Irene´s Mother, and she is a carrier as well. Irene´s father, Louis, is not a carrier, so she could have inherited a dominant allele from her father and a recessive allele from her mother, X⁺X⁻, or she could have inherited two dominant alleles from both her parents X⁺X⁺. This is not proof enough of Irene being heterozygous.
- The fact that Alexandra, Irene´s sister, was also a carrier does not say anything about Irene´s genotype, because they could both share the same genotype or not. This is not proof of Irene being heterozygous.
- Frederick (her brother) was hemophilic. He received a recessive allele from Alice, but this does not say anything about Irene´s genotype.
- The fact that Waldemar (her son) was hemophilic, is the best evidence to prove that Irene was heterozygous for hemophilia. Walderman received the Y chromosome from his father and an X chromosome from his mother. The X chromosome that he received from his mother carried the recessive allele for the trait, and this is why he had hemophilia. This means that there is no best evidence for Irene´s genotype than her son´s genotype.
