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Rainbow [258]
3 years ago
11

Help me please!! worth 12 points

Mathematics
1 answer:
eduard3 years ago
6 0
To be honest  the numbers up there are like dividing like it say 2 or -2 so i would be 2/-2 i hope these helps i really do 
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What are the factors of 3x²+7x-20?
Leya [2.2K]
3x^2+7x-20=0\\\\a=3;\ b=7;\ c=-20\\\\\Delta=b^2-4ac\\\\x_1=\frac{-b-\sqrt\Delta}{2a};\ x_2=\frac{-b+\sqrt\Delta}{2a}\\\\\Delta=7^2-4\cdot3\cdot(-20)=49+240=289;\ \sqrt\Delta=\sqrt{289}=17\\\\x_1=\frac{-7-17}{2\cdot3}=\frac{-24}{6}=-4;\ x_2=\frac{-7+17}{2\cdot3}=\frac{10}{6}=\frac{5}{3}\\\\\\3x^2+7x-20=3(x+4)(x-\frac{5}{3})\\\\\\3x^2+7x-20=0\iff x=-4\ \vee\ x=\frac{5}{3}
4 0
3 years ago
Please help me with this problem
JulsSmile [24]

Answer:

37°

Step-by-step explanation:

since <1 +<6=180° (sum of co interior angles)

143°+<6= 180°

<6=180°-143°

<6= 37°

m<6=m<7 (vertically opposite angles)

Hence m<6=37°

m<7=37°

5 0
2 years ago
Describe each of the following transformation that maps the figures described below. Be specific by naming lines of reflection,
Flura [38]

Answer:

Part A: Figure 1 → Figure 4

Rigid Transformation

Equivalent to a reflection about the origin, or a rotation of 180° clockwise or anticlockwise about the origin which are types of rigid transformation

Part B: Figure 2 → Figure 5

Similarity transformation

Figure 5 is Figure 2 dilated by a scale factor of 1/2, which is a form of a similarity transformation

Step-by-step explanation:

Part A: Figure 1 → Figure 4

The coordinates of the vertices of the preimage are;

(5, 10), (2, 4), (9, 2)

The coordinates of the vertices of the image are;

(-9, -2), (-2, -4), (-5, -10)

Which is equivalent to a reflection about the origin, or a rotation of 180° clockwise or anticlockwise about the origin

Part B: Figure 2 → Figure 5

The coordinate points of figure 2 are;

(-9, 2), (-5, 10), and (-2, 4)

The coordinate points of figure 5 are;

(1, 2), (2.5, -1), and (4.5, 3)

The lengths of the sides of figure 2 are;

√((10 - 2)² + ((-5) - (-9))²) = 4·√5

√((10 - 4)² + ((-5) - (-2))²) = 3·√5

√((2 - 4)² + ((-9) - (-2))²) = √53

The lengths of the sides of figure 5 are;

√(((-1) - 2)² + (2.5 - 1)²) = (3·√5)/2

√((4.5 - 2.5)² + (3 - (-1))²) = 2·√5

√((4.5 - 1)² + (3 - 2)²) = (√53)/2

Therefore. Figure 5 is Figure 2 dilated by a scale factor of 1/2

Therefore, given that the sides of Figure 2 and Figure 5 are rotated by 180°

We have;

Figure 5 is obtained as follows;

1) The rotation of figure 2 by 180°, clockwise or anticlockwise about the origin to get;

(-9, 2), (-5, 10), and (-2, 4) → (9, -2), (5, -10), and (2, -4)

2) The image is translated left by 1 blocks and up by 6 blocks as follows;

(9, -2), (5, -10), and (2, -4)  → (8, 4), (4, -4), and (1, 2)

3) The image is then dilated by a scale factor of 1/2  with a center of dilation of (1, 2) to get;

Preimage (8, 4), (4, -4), and (1, 2) → Image (1, 2), (2.5, -1), and (4.5, 3).

8 0
3 years ago
5. Pete and Mike share £420 in the ratio 5:1. How much does Pete have.
sdas [7]

Answer:

5+1=6

5/6 x420

5x70=350

Step-by-step explanation:

7 0
2 years ago
Write an equation of the line that passes through (2,-1) and (-3,3)
Anuta_ua [19.1K]

Answer:

Y=-4/5x+3/5y

Step-by-step explanation: first get the gradient

3--1/-3-2

=4/-5

y-3/x+3=4/-5

-5y+15=4x+12

-5y=4x-3

y=4/-5x+3/5

6 0
3 years ago
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