Step-by-step explanation:
- square root of 10 is irrational because it is less than zero. - square root of 10 is irrational because it is not a whole number.
Upon prime factorizing 10 i.e. 21 × 51, 2 is in odd power. Therefore, the square root of 10 is irrational.
Answer:
The slope is -1/1 or just -1.
(When you need to plot the slope, you use -1/1 to use the strategy Rise/Run or Rise over Run.
If you look at the point (-3,1) From that point, you go down -1 and you run to the side for a positive 1.
Once you do that you'll land at (-2,0) and you can keep on repeating this and you'll see that it lands on the points on the line.
Hope this helps! Please feel free to ask any questions if needed! :)
Answer:
solution :
x = 4
Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
5*(x-10)-(30-15*x)=0
Step by step solution :
Step 1 :
Equation at the end of step 1 :
5 • (x - 10) - (30 - 15x) = 0
Step 2 :
Step 3 :
Pulling out like terms :
3.1 Pull out like factors :
20x - 80 = 20 • (x - 4)
Equation at the end of step 3 :
20 • (x - 4) = 0
Step 4 :
Equations which are never true :
4.1 Solve : 20 = 0
Step-by-step explanation:
Answer:
Concept: Modeling expressions
- We are given the equation

- We want to find the time after 0.75 seconds given that t is represented in seconds.
- Hence we do

- Hence we get the answer to 191 feet
Considering that you are planning the trip with limited budget and only for 4 days (=96h) you must value both time and money when doing it.
If you use the bus you spend $75 + $75=$150 and 12h + 12h = 24h. This means you spend $150 to enjoy 96h - 24h = 72h of actually camping. This means you pay $150/72h = $2,08 per hour of actual camping.
On the other hand if you choose the plane you spend $150 + $ 150 = $300 and 1,5h + 1,5h = 3h. This means you spend $300 to enjoy 96h - 3h = 93h. This means you pay $300/93h = $3,22 per hour of actual camping.
Considering all that, taking the bus his the most cost-effective option (and the cheaper one also).