Let us say that,
<span>A = perimeter of football field of the 1st
school</span>
B = perimeter of football field of the 2nd school
C = perimeter of football field of the 3rd school
So that:
A = 320 m
B = 360 m
C = 400 m
So the first thing we have to do to find for the minimum
laps to make is to divide every perimeter by the smallest one, therefore divide
all by 320 m, hence:
A’ = 1
B’ = 1.125
C’ = 1.25
Now multiply everything by a number such that all laps
will be a whole number, in this case multiply everything by 8:
A’ = 8
B’ = 9
C’ = 10
Hence the laps to run are:
<span>8, 9 and 10</span>
Answer:
where are the options
Step-by-step explanation:
The <u>brackish</u> marshes are the most diverse.
<h3>What are
Brackish Marshes?</h3>
These are the sectors that are found in the estuaries that border the coasts, which is why they contain fresh and salt water, which is usually called brackish, where a great diversity of animals live, both salt water and adaptable to brackish water.
Within the fauna of this sector, you can find the archer fish, the <em>Monodactylus argenteus</em> and <em>Scatophagus argus</em>.
If you want to learn more about Marshes, you can visit the following link: brainly.com/question/17326027
233 to 1 significant figure :
233 ≈ 200 (1 s.f.)
