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shtirl [24]
4 years ago
8

A combination lock has digit from 0 to 39 on it . three numbers are required to open the lock. how many combinations are possibl

e if you cannot have the same digit twice in a row
Mathematics
1 answer:
Mashutka [201]4 years ago
6 0
<span>A combination lock has digits from 0 to 39. three numbers are required to open.
how many combinations are possible if you cannot repeat any digits?
40*39*38 = 59280
--------------------------
How many combinations are possible if you cannot have the same digit twice in a row?

Call the number F, S, and T for 1st, 2nd, and 3rd
F is 1/40
S is any but F, = 1/39
T is any but S, = 1/39
40*39*39 = 60840 </span>
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Answer:

L1 = 18 cm

W1 = 14 cm

A1 = 252 cm²

Step-by-step explanation:

Since the small rectangle is ½ the scale drawing of the original figure, therefore the dimensions of the smaller rectangle would be half of that of the original.

Thus:

Length (L) of the original = 36 cm

Length (L1) of the smaller rectangle = ½(36) = 18 cm

Width (W) of the original = 28 cm

Length (W1) of the smaller rectangle = ½(28) = 14 cm

Area (A1) of the smaller rectangle = L1 × W1 = 18 × 14 = 252 cm²

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3 years ago
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What value of x makes the equation true?
gtnhenbr [62]

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nadya68 [22]

Answer:

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Step-by-step explanation:

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This means that the answers are:

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I do not understand your answers though. Answer A makes no sense, answer B is 221, answer C is 115, and answer D also does not make sense. If you could clarify this portion, maybe I can help you find your alphabetic answer

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