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trapecia [35]
4 years ago
6

Solve this quadratic equation by completing the square.

Mathematics
1 answer:
nadya68 [22]4 years ago
3 0

Answer:

x=-3+\sqrt{27}\\  x=-3-\sqrt{27}

Step-by-step explanation:

Let's find our C value for the quadratic equation.

(\frac{6}{2})^{2} = 9

That is our C. Since we added 9 to one side, we have to do the same to the other. We get:

x^{2} +6x + 9 = 18 + 9\\x^{2} +6x + 9 = 27

Now, lets form the left side as a binomial squared.

(x+3)^{2} = 27

Let's square both sides now:

x+3 = (+/-)\sqrt{27}

Now, we subtract 3 from both sides to isolate the variable, X:

x= -3(+/-)\sqrt{27}

This means that the answers are:

x=-3+\sqrt{27}\\  x=-3-\sqrt{27}

I do not understand your answers though. Answer A makes no sense, answer B is 221, answer C is 115, and answer D also does not make sense. If you could clarify this portion, maybe I can help you find your alphabetic answer

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The spray from a sprinkler reaches 21 feet from the sprinkler and creates a circle as it spins. What is the circumference of the
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3 years ago
ACBM is a segment of a circle such
tatiyna

Answer:

a. 8.94 cm  b. 127°  c. 12.37 cm²

Step-by-step explanation:

a. Since CM = 4 cm is the perpendicular bisector of AB = 16 cm and r is the radius off the circle. From Pythagoras' theorem,

r² = (AB/2)² + CM²

r = √[(AB/2)² + CM²]

Substituting the values of the variables into r, we have

r = √[(16/2)² + 4²]

r = √[8² + 4²]

r = 4√[2² + 1²]

r = 4√[4 + 1]

r = 4√5 cm

r = 8.94 cm  

b. We know that the length of a chord L = 2rsin(θ/2) where r is the radius of the circle, and θ is the angle subtended by the chord AB.

Since L = 2rsin(θ/2)    and L = AB = 16 cm,

L/2r = sin(θ/2)

taking sine inverse of both sides, we have

θ/2 = sin⁻¹(L/2r)

multiplying both sides by 2, we have

θ = 2sin⁻¹(L/2r)        

substituting the values of the variables, we have

θ = 2sin⁻¹[16/(2 × 8.94)]

θ = 2sin⁻¹[16/17.88]

θ = 2sin⁻¹[0.8949]

θ = 2 × 63.49°

θ = 126.98°

θ ≅ 127°

c. The area of a segment A is given by

A = (θπ/360 - sinθ)r²/2 where θ is the angle subtended by the segment and r = radius of the circle

since θ ≅ 127° and r = 4√5 cm, substituting these values into A, we have

A = (127°π/360 - sin127°)(4√5)²/2

A = (398.93/360 - 0.7988)40

A = (1.1081 - 0.7988)40

A = 0.3093 × 40

A = 12.372 cm²

A ≅ 12.37 cm²

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What is the range of 24.35cm 22.51cm 20.98cm 30.33cm and 30.98cm ?
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The range is the variance between the smallest and largest value in the data set. The range is 10; calculated by taking 20.98 and subtracting it from 30.98.
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