If apples cost $0.75 each and oranges cost $0.50 each, what combinations of the fruits can be bought for under $10?

Niko uses 12 marshmallows and 8 graham crackers to make 4 s'mores.

Lerok [7]

Answer:

6 crackers, 9 marshmallows

Step-by-step explanation:

You have to divide to find how many graham crackers and marshmallows are needed to make 1 s'more:

8 / 4 = 2, so 2 crackers per s'more. Then,

12 / 4 = 3, so 3 marshmallows per s'more. Now that we know this, all we have to do is multiply each number by 3 to make 3 s'mores.

2 * 3 = 6, so 6 crackers, and

3 * 3 = 9, so 9 marshmallows.

:)

3 0

3 years ago

Read 2 more answers

Helppppp on alllll plz

igomit [66]

a. $150

b. 150+20x $\geq$ 630

20x $\geq$ 480

x $\geq$ 24

c. 150+20x $\geq$ 750

20x $\geq$ 600

x $\geq$ 30

d. 150+20x $\leq$ 950

20x $\leq$ 800

x $\leq$ 40

Hope Your Thanksgiving Goes Well, Here's A Turkey

-TheKoolKid1O1

3 0

3 years ago

13 POINTS- please help me

allsm [11]

Answer:

See explanation

Step-by-step explanation:

16. Two parallel lines are cut by transversal. Angles with measures $(6x+20)^{\circ}$ and $(x+100)^{\circ}$ are alternate exterior angles. By alternate exterior angles, the measures of alternate exterior angles are the same:

$6x+20=x+100\\ \\6x-x=100-20\\ \\5x=80\\ \\x=16$

Then

$(6x+20)^{\circ}=(6\cdot 16+20)^{\circ}=116^{\circ}\\ \\(x+100)^{\circ}=(16+100)^{\circ}=116^{\circ}$

17. Two parallel lines are cut by transversal. Angles with measures $(2x+12)^{\circ}$ and $(3x-22)^{\circ}$ are alternate interior angles. By alternate interior angles, the measures of alternate interior angles are the same:

$2x+12=3x-22\\ \\2x-3x=-22-12\\ \\-x=-34\\ \\x=34$

Then

$(2x+12)^{\circ}=(2\cdot 34+12)^{\circ}=80^{\circ}\\ \\(3x-22)^{\circ}=(3\cdot 34-22)^{\circ}=80^{\circ}$

18. Two parallel lines are cut by transversal. Angles with measures $(6x-7)^{\circ}$ and $(5x+10)^{\circ}$ are alternate exterior angles. By alternate interior angles, the measures of alternate exterior angles are the same:

$6x-7=5x+10\\ \\6x-5x=10+7\\ \\x=17$

Then

$(6x-7)^{\circ}=(6\cdot 17-7)^{\circ}=95^{\circ}\\ \\(5x+10)^{\circ}=(5\cdot 17+10)^{\circ}=95^{\circ}$

19. The diagram shows two complementary angles with measures $2x^{\circ}$ and $56^{\circ}$ . The measures of complementary angles add up to $90^{\circ},$ then

$2x+56=90\\ \\2x=90-56\\ \\2x=34\\ \\x=17$

Hence,

$2x^{\circ}=2\cdot 17^{\circ}=34^{\circ}$

Check:

$34^{\circ}+56^{\circ}=90^{\circ}$

20. Angles $\angle 1$ and $\angle 2$ are vertical angles. By vertical angles theorem, vertical angles are congruent, so

$m\angle 1=m\angle 2\\ \\5x+7=3x+15\\ \\5x-3x=15-7\\ \\2x=8\\ \\x=4$

Hence,

$m\angle 1=(5x+7)^{\circ}=(5\cdot 4+7)^{\circ}=27^{\circ}\\ \\m\angle 2=(3x+15)^{\circ}=(3\cdot 4+15)^{\circ}=27^{\circ}$

21. $\angle 5$ and $\angle 8$ are supplementary. The measures of supplementary angles add up to $180^{\circ},$ so

$m\angle 5+m\angle 8=180^{\circ}\\ \\3x-40+7x-120=180\\ \\10x-160=180\\ \\10x=180+160\\ \\10x=340\\ \\x=34$

Therefore,

$m\angle 5=(3x-40)^{\circ}=(3\cdot 34-40)^{\circ}=62^{\circ}\\ \\m\angle 8=(7x-120)^{\circ}=(7\cdot 34-120)^{\circ}=118^{\circ}\\ \\62^{\circ}+118^{\circ}=180^{\circ}$

7 0

3 years ago

Fill in the blank. In the triangle below, x =

Evgesh-ka [11]

Hello, i definitely don’t know i just need to answer something sorry

4 0

2 years ago

Which number is larger? (1 mark)<br><br> 0.67 or<br> 2/3

KengaRu [80]

Answer:

0.67

Step-by-step explanation:

2/3= to 0.66 which means 0.67 would be technally larger than 0.66

8 0

2 years ago