The absolute parent function is |X|.
It is Choice B. because all the other choices are transformations of the parent function except for Choice D. which is just a line on the x-axis.
The polynomial function of the least degree with integral coefficient that has the given zeros is <span>y = (x+2)(x-2)(x-4)(x-6). I hope you are satisfied with my answer and feel free to ask for more if you have questions and further clarifications about the said problem.</span>
We know that sin2x=2sinxcosx
(search the net for proof if you wish)
So the original equation becomes
2sinxcosx-sinx=0
The two terms both have sinx that can be taken out to get:
sinx(2cosx-1)=0
This is true if sinx=0 or 2cosx-1=0 , rewritten: cosx=1/2
sinx=0 than x=2kπ
cosx=1/2 than x=π/3+2kπ
where k is an integer
Answer:
x= -30
Step-by-step explanation:
√3×sinx+cosx=0
√3sinx=-cosx
√3sinx/-cosx=1
-sinx/cosx=1/√3
-tanx=1/√3
(tan(180-30))=1/√3
tan(-30)=1/√3
Therefore, x= -30